下面的脚本在手机上的两个模拟器上使用 Swift 2 工作正常。更新到 swift 3 后,该脚本在模拟器上运行良好,但在为手机构建时会引发错误 - 下标的使用模棱两可 -
let aObject = linkJSON[index] as! [String : AnyObject]
我已尝试更改行以使用 Any,但是错误没有更改。
因此,完整的代码是 -
class ViewController: UIViewController {
@IBOutlet weak var tableView: UITableView!
var orgs: [String] = []
var icon: [String] = []
var address1: [String] = []
var address2: [String] = []
var address3: [String] = []
var address4: [String] = []
var postcodes: [String] = []
var phone: [String] = []
var email: [String] = []
var website: [String] = []
override func viewDidLoad() {
super.viewDidLoad()
let url=URL(string:"http://webdata.net/service.php")
do {
let allLinksData = try Data(contentsOf: url!)
let allLinks = try JSONSerialization.jsonObject(with: allLinksData, options:.allowFragments) as! [String : AnyObject]
if let linkJSON = allLinks["organisations"] {
for index in 0...linkJSON.count-1 {
let aObject = linkJSON[index] as! [String : AnyObject]
orgs.append(aObject["org"] as! String)
icon.append(aObject["icon"] as! String)
address1.append(aObject["address1"] as! String)
address2.append(aObject["address2"] as! String)
address3.append(aObject["address3"] as! String)
address4.append(aObject["address4"] as! String)
postcodes.append(aObject["postcode"] as! String)
phone.append(aObject["phone"] as! String)
email.append(aObject["email"] as! String)
website.append(aObject["website"] as! String)
}
}
print(orgs)
self.tableView.reloadData()
}
catch {
}
}
可能是因为星期一,但我在这里有一个空白。
谢谢
弓帽
我建议你替换
if let linkJSON = allLinks["organisations"] {
跟
if let linkJSON = allLinks["organisations"] as? [[String: AnyHashable]] {
然后,您无需强制解开linkJSON[index]
,只需执行即可
let aObject = linkObject[index]