我正在使用python 3.2和Tkinter自由编写一个简单的计算器。当我运行我的程序时,它在文本字段中打印只有在事件之后才需要打印的数字。我做错了什么?
from tkinter import Button, Entry, Tk, Widget
from calculate import calculate
def output():
equation = text.get()
result = calculate(equation)
if result != False:
text.delete(0, 100)
text.insert(0, result)
else:
text.delete(0, 100)
text.insert(0, 'Error')
def insert_num(i):
text.insert(100, i)
root=Tk()
root.config(width=265, height = 320)
text=Entry(root, font='Arial 14')
text.config(width=22)
text.place(x=10, y=20)
class Num(Widget):
def __init__(self, root, text, font, width, height, x, y, command):
self.widget = Button(root, text=text, font=font, command=command)
self.widget.config(width=width, height=height)
self.widget.place(x=x, y=y)
font = 'Arial 14'
plus = Num(root, '+', font, 3, 1, 10, 50+10, None)
minus = Num(root, '-', font, 3, 1, 10, 100+10, None)
divide = Num(root, '/', font, 3, 1, 10, 150+10, None)
multiple = Num(root, '*', font, 3, 1, 10, 200+10, None)
list = ['','','','','','','','','']
x = 50+10; y = 100+10
for i in range(0, 9):
list[i] = Button(root, text=i+1, font='Arial 14')
list[i].bind('<Button-1>', insert_num(i+1))
list[i].config(width = 3, height = 1)
list[i].place(x=x, y=y)
x = x + 50
if i == 2 or i == 5:
x = 50+10; y = y + 40+10
root.mainloop()
输出:123456789
list[i].bind()
的第二个参数应该是一个函数,而不是对函数的调用。对于insert_num(i+1)
,您调用该函数,并将None
绑定到单击事件。将insert_num
替换为:
def insert_num(i):
return lambda event: text.insert(100, i)