mock: BadMethodCallException:方法Mockery_0_Foo::bar()在这个mock对象

Question

我不能让mock创建一个简单的假人:

<?php
require_once '../vendor/autoload.php'; // composer autoload mockery
class Foo {
    private $required;
    public function __construct($required){
        $this->required = $required;
    }
    public function bar(){
        // do stuff with $this->required
    }
}
class FooTest extends PHPUnit_Framework_TestCase  {
    public function testBar(){
        $mock = Mockery::mock('Foo');
        $mock->bar();
    }
}

运行PHPUnit测试给出错误:

BadMethodCallException: Method Mockery_0_Foo::bar() does not exist on this mock object

我做错了什么?

Answer 1

如果你想在"Foo"类和模拟"Required"对象上做php单元测试。就像下面这样做:

class Foo {
    private $required;
    public function __construct(Required $required){
        $this->required = $required;
    }
    public function bar(){
        return $this->required->getTextFromBarTable();
    }
}
class FooTest extends PHPUnit_Framework_TestCase  {
    public function testBar(){
        $mock = Mockery::mock('Required'); // Dummy, There are no properties or methods.
        /**
        * Stub "getTextFromBarTable" method of Required class 
        * and fakes response by returning "return this text".
        */
        $mock->shouldReceive('getTextFromBarTable') 
             ->andReturn('return this text');
        // create "Foo" Object by using $mock instead of actual "Required" Object.
        $foo = new Foo($mock); 
        $response = $foo->bar();
        $this->assertEqual('return this text', $response);
    }
}

你必须不要存根或模拟类，你想做单元测试。只需在"Required"之类的依赖类上执行即可。

我们使用STUB或MOCK来分离可能影响我们要测试的方法的内部逻辑的外部逻辑。在这种情况下，我假设Required类具有"getTextFromBarTable"方法，该方法将连接并从数据库中获取"文本"字段。如果我们的数据库没有文本字段，"testBar"方法将被破坏。为了摆脱外部问题，我在"Required"上做了存根，每次我都使用"getTextFromBarTable"方法。它总是会返回"return this text"

Answer 2

我必须显式地声明mock生成哪些方法的存根:

class FooTest extends PHPUnit_Framework_TestCase  {
    public function testBar(){
        $mock = Mockery::mock('Foo');
        $mock->shouldReceive('bar');
        $mock->bar();
    }
}

我很好奇是否有一种方法可以解决这个问题，或者:

1. 隐式捕获Foo中定义的所有方法调用，或
2. 隐式捕获所有方法调用，无论它们是否在Foo
中定义。