如何在用户触摸精灵时更改它的颜色

Question

我是iOS开发和SpriteKit的新手。我正在制作一个游戏，我需要在用户触摸它时更改精灵颜色。实际上，我有三种确定的颜色。角色以红色开始。当用户触摸它时，它会变成蓝色。如果用户再次触摸，它将变为黑色。如果用户再触摸它一次，它又变红了。

在触摸开始的方法中，我正在尝试类似的东西：

if (playerBar.color == [SKColor redColor]) {
    playerBar.color = [SKColor blueColor];
} else if (playerBar.color == [SKColor blueColor] {
    playerBar.color = [SKColor blackColor];
} else if (playerBar.color == [SKColor blackColor]) {
    playerBar.color = [SKColor redColor];
}

有人可以帮助我吗？多谢。

Answer 1

!!很抱歉这么长的答案，在底部你可以找到 Swift 和 Objective-C 的完整解决方案

您可以使用以下方法更改带有动画的 SKSpriteNode 的颜色，这些颜色看起来会更好：

目标-C：

   SKAction *changeColorAction = [SKAction colorizeWithColor:[SKColor blueColor] colorBlendFactor:1.0 duration:0.5];
   [myLabel runAction:changeColorAction];

迅速：

   let changeColorAction = SKAction.colorizeWithColor(SKColor.blueColor(), colorBlendFactor: 1.0, duration: 0.5)
   playerBar.runAction(changeColorAction)

这是 Swift 中针对您的问题的完整解决方案，包括触摸检查、颜色比较和更改。实际上，您检查节点当前颜色是否等于SKColor的方法不行。因此，我向您展示我的解决方案，这可能不是很好，但有效。

首先，在初始化玩家栏精灵节点的位置，给它起一个名字，如下所示：

  playerBar.name = "playerBar"

之后，使用下面的代码进行 SKColor 比较(不是很准确，但在这种情况下有效(，也用于触摸检查节点和颜色更改。

  func isEqualColor(color: SKColor, toColor: SKColor) -> Bool {
    let color1Components = CGColorGetComponents(color.CGColor)
    let color2Components = CGColorGetComponents(toColor.CGColor)
    if ((color1Components[0] != color2Components[0]) || //red
       (color1Components[1] != color2Components[1]) || //green
       (color1Components[2] != color2Components[2]) || //blue
       (color1Components[3] != color2Components[3])) { //alpha
        return false
    }
    return true
  }
  override func touchesBegan(touches: NSSet, withEvent event: UIEvent) {
        /* Called when a touch begins */
      for touch: AnyObject in touches {
        let location = touch.locationInNode(self)
        let nodes = self.nodesAtPoint(location) as [SKNode]
        for node in nodes {
          if node.name == "playerBar" {
            let spriteNode = node as SKSpriteNode
            var color = SKColor.redColor()
            if isEqualColor(spriteNode.color, toColor: SKColor.redColor()) {
              color = SKColor.blueColor()
            } else if isEqualColor(spriteNode.color, toColor: SKColor.blueColor()) {
              color = SKColor.blackColor()
            }
            let changeColorAction = SKAction.colorizeWithColor(color, colorBlendFactor: 1.0, duration: 0.5)
            spriteNode.runAction(changeColorAction) {
              spriteNode.color = color //On completion of action, we set color so after in comparison method not have conflicts while comparing color components
            }
          }
        }
      }
    }

我不能让你没有一个 Obejctive-C 解决方案来解决这个问题:)因此，您需要在初始化时为您的玩家Bar SpriteNode命名。

playerBar.name = "playerBar";

将此方法用于完整解决方案后：

- (BOOL)isEqualColor:(SKColor *)color1 toColor:(SKColor *)color2
{
  const CGFloat* color1Components = CGColorGetComponents([color1 CGColor]);
  const CGFloat* color2Components = CGColorGetComponents([color2 CGColor]);
  if ((color1Components[0] != color2Components[0]) || //red
      (color1Components[1] != color2Components[1]) || //green
      (color1Components[2] != color2Components[2]) || //blue
      (color1Components[3] != color2Components[3])) { //alpha
    return NO;
  }
  return YES;
}
- (void)touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event {
    /* Called when a touch begins */
    for (UITouch *touch in touches) {
      CGPoint location = [touch locationInNode:self];
      NSArray *nodes = [self nodesAtPoint:location];
      for (SKNode *node in nodes) {
        if ([node.name isEqualToString:@"playerBar"]) {
          SKSpriteNode *spriteNode = (SKSpriteNode *)node;
          SKColor *color = [SKColor redColor];
          if ([self isEqualColor:spriteNode.color toColor:[SKColor redColor]]) {
            color = [SKColor blueColor];
          } else if ([self isEqualColor:spriteNode.color toColor:[SKColor blueColor]]) {
            color = [SKColor blackColor];
          }
          SKAction *changeColor = [SKAction colorizeWithColor:color colorBlendFactor:1.0 duration:0.5];
          [spriteNode runAction:changeColor completion:^{
            spriteNode.color = color; //On completion of action, we set color so after in comparison method not have conflicts while comparing color components
          }];
        }
      }
    }
}

Answer 2

假设您正确注册了触摸，则必须为玩家Bar分配一个colorBlendFactor

playerBar.colorBlendFactor = 1.0;

colorBlendFactor 是一个浮点值，用于描述颜色如何与精灵的纹理混合。

Answer 3

-(void)changeColor
{
    int color = 1;
    if (color == 1 || color > 3) {
        playerBar.color = [SKColor redColor];
        color = 1;
    }if else(color == 2) {
        playerBar.color = [SKColor blueColor];
    }if else(color == 3) {
        playerBar.color = [SKColor blackColor];
    }
    color++;
}
-(void)touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event
{
    UITouch *touch = [touches anyObject];
    CGPoint touchLocation = [touch locationInNode:self.scene];
    SKNode *node = [self nodeAtPoint:touchLocation];
    if ([node.name isEqualToString:@"yourSpriteName"]) {
        [self changeColor];
    }
}