我正在开发游戏,它是用qml和pyqt编写的,但应该分为两个窗口(启动器+游戏)。在这两个 qml 文件之间切换的正确方法是什么?我不想使用 QmlLoader,因为它不会调整窗口大小,而且需要很多信号!我也在尝试这个变体:
view.engine().clearComponentCache()
view.setSource(source())
但它没有用(QML 窗口停止工作... - 经典窗口错误,但是在 pycharm 控制台中没有写入错误)
我的代码如下所示:
from PyQt5.QtCore import pyqtProperty, QRectF, QUrl, QObject, pyqtSignal, pyqtSlot, QVariant
from PyQt5.QtGui import QColor, QGuiApplication, QPainter, QPen
from PyQt5.QtQml import qmlRegisterType
from PyQt5.QtQuick import QQuickItem, QQuickPaintedItem, QQuickView
from PyQt5 import QtNetwork as QN
from PyQt5 import QtCore as QC
from multiprocessing import Process
import server as S
import client as C
from time import time, sleep
class Launcher(QQuickItem):
PORTS = (9998, 9999)
PORT = 9999
SIZEOF_UINT32 = 4
changeUI = pyqtSignal()
changeName= pyqtSignal(int, str)
connection= pyqtSignal(int, bool)
connected= pyqtSignal(QVariant)
@pyqtSlot(name="startGame")
def start_game(self):
#app.exit()
startGame()
print ("startGame")
@pyqtProperty(str)
def name(self):
print ("return name")
return self._name
@name.setter
def name(self, n):
print ("set name")
self._name= n
@pyqtSlot(name= "terminate")
def terminate_server(self):
if not self.server: return
self.server.terminate() #Bye
self.server.join()
#self.bstopServer.setEnabled(False)
#self.bserver.setEnabled(True)
self.server = None
@pyqtSlot()
def _quit(self):
if self.server:
self.server.terminate() #Bye
self.server.join()
app.exit()
@pyqtSlot()
def back(self):
self.client.disconnect()
def __init__(self, parent=None):
super(Launcher, self).__init__(parent)
self.socket= QN.QTcpSocket() #Yeah, the game will be over internet
self.server = None
self.client = None #client is a QObject
self._turnedOn = False
self._players = 1
self._name = "YourName"
class Game(QQuickItem):
def __init__(self, parent= None):
super(Game, self).__init__(parent)
self.client = True #I should get the client from the launcher, but I don´t know how
def startGame():
view.engine().clearComponentCache()
view.setResizeMode(QQuickView.SizeViewToRootObject)
view.showFullScreen()
view.setSource(
QUrl.fromLocalFile(
os.path.join(os.path.dirname(__file__),'Game.qml')))
view.show()
#app.exec_()
def startLauncher():
view.engine().clearComponentCache()
view.setResizeMode(QQuickView.SizeViewToRootObject)
view.setSource(
QUrl.fromLocalFile(
os.path.join(os.path.dirname(__file__),'Launcher.qml')))
view.show()
app.exec_()
if __name__ == '__main__':
import os
import sys
app = QGuiApplication(sys.argv)
qmlRegisterType(Launcher, "ParanoiaLauncher", 1, 0, "App")
qmlRegisterType(Game, "ParanoiaGame", 1, 0, "App")
view = QQuickView()
startLauncher()
正如你可能看到的,我的结构有点混乱,因为我是第一次做这种切换行为,所以我真的不知道,应该如何正确地完成它......欢迎每一个建议!:)
我不得不在同一时间面对同样的问题。相反,我一遍又一遍地使用相同的QQuickView
加载相同的组件,我在 QML 中创建了一个组件作为内容容器,并将所需的组件作为其子组件加载。每次设置新组件时,我们都会销毁当前组件并再次将新组件设置为子组件。
// ContentFrame.qml
Item{
width: 800
height: 600
Item{
id: contentContainer
anchors.fill: parent
anchors.margins: 4
}
}
首先,请原谅我,但功能代码是用C++编写的,但我认为这个概念可以理解。我制作了该过程的缩短版本,我希望它可以移植到 python。
为了加载 ContentFrame 组件,我使用了从 QQuickView (ViewManager) 派生的类,该类具有一个名为 setView 的方法。此方法加载一个组件(在您的情况下为启动器或游戏),将其设置为contentContainer
的子组件,并将其anchor.fill
设置为填充整个父组件。
ViewManager::ViewManager() : QQuickView("ContentFrame.qml")
{
// More ctor code
}
// Other stuff
void ViewManager::setView(const QString &filename)
{
QQuickItem *mostTopItem = rootObject(); //QQuickView::rootObject() method
QQuickItem *contentItem->findChild<QQuickItem*>("contentContainer");
if(m_current != NULL)
{
m_current->setProperty("visible", false);
}
// Call a method to load the component and create an instance of it
QQuickItem *newItem = createOurComponentFromFile(filename);
newItem->setProperty("parent", QVariant::fromValue<QObject*>(contentItem));
// When "delete item" in C++, the object will be destroyed in QQmlEngine
// in pyqt???
QQmlEngine::setObjectOwnership(newItem, QQmlEngine::CppOwnership);
newItem->setProperty("anchors.fill", QVariant::fromValue<QObject*>(contentItem));
// Cleanup current object
if(m_current != NULL)
{
delete m_current;
}
m_current = newItem;
}
还有更多的代码,但ViewManager的核心是这种方法。我在这里不打电话给QQmlEngine::clearComponentCache()
,因为我多次加载相同的组件,但在您的情况下,这可能是一个好主意。