计算一周中从星期一到星期六的天数

Question

在我的表单中，我有一个数据字段，用于选择一周中的哪一天！例如，如果我选择今天23-03-2012星期五，我需要获得从上一个星期一到下一个星期六的一系列天数。

阵列：

[0],[19-03-2012],[Monday]
[1],[20-03-2012],[Monday]
[2],[21-03-2012],[Wednesday]
[3],[22-03-2012],[Monday]
[4],[23-03-2012],[Friday]
[5],[24-03-2012],[Saturday]

我怎么能在一周中的任何一天都注意到变化？感谢

Answer 1

此函数将返回date周中的所有日期的数组，即星期一到星期六。

function GetDaysOfWeek(date)
{
    var days = new Array();
    for (var i = 0; i < 6; i++)
    {
        days[i] = new Date(date.getYear(),
                           date.getMonth(),
                           date.getDate() - date.getDay() + 1 + i);
    }
    return days;
}

Answer 2

可以尝试MomentJs：http://momentjs.com/docs/

一些例子：

moment().day(-7); // set to last Sunday (0 - 7) 
moment().day(7); // set to next Sunday (0 + 7)
moment().day(10); // set to next Wednesday (3 + 7)
moment().day(24); // set to 3 Wednesdays from now (3 + 7 + 7 + 7)

Answer 3

用于显示一周中的当前日期：

 var now = new Date();
 var dayNames = ["Sunday","Monday","Tuesday","Wednesday","Thursday","Friday","Saturday"];
 document.write("Today is " + dayNames[now.getDay()] + ".");

Answer 4

• 第一次找到今天的日期
• 查找最后一个星期一（包括今天）
• 显示该日期及其后的5天（星期二至星期六）

---

var d = new Date();
if (d.getDay()==0){
   d.setDate(d.getDate() + 1);
}
​while (d.getDay() != 1){
    d.setDate(d.getDate() - 1);
}
var days = new Array();
for (var i = 0; i < 6; i++){
  days[i] = d.getDate() + i;
}
return days;

Answer 5

试试这个：

var dayString = ["Sunday","Monday","Tuesday","Wednesday","Thursday","Friday","Saturday"];
var now = new Date();
var currentDay = now.getDay(); // return 0 for Sunday, 6 for Saturday
var result = [];
var tempDate = new Date(now.getTime());
tempDate.setDate(now.getDate()-(currentDay+6)%7); // now tempDate is previous Monday
while(tempDate.getDay()!=0) {
    var currentMonth = tempDate.getMonth()+1;
    if(currentMonth<10) currentMonth = "0"+currentMonth;
    result.push([tempDate.getDay()-1,tempDate.getDate()+"-"+currentMonth+"-"+tempDate.getFullYear(),dayString[tempDate.getDay()]]);
    tempDate.setDate(tempDate.getDate()+1);
}
console.log(result);

Answer 6

下面这样的东西会起作用，我相信你可以把格式设置到你想要的地方。

// Assuming d is a date object
function getDateArray(din) {
  // Add leading zero to one digit numbers
  function aZ(n){return (n<10? '0':'') + n;}
  var days = ['Sunday','Monday','Tuesday','Wednesday',
              'Thursday','Friday','Saturday'];
  var d = new Date(din); // Don't wreck input date  
  var dn = d.getDay();
  var a = [];
  var i = 6; // length of day array
  if (!dn) {
    // It's Sunday, what now? 
    return ['Sunday!'];
  }
  d.setDate(d.getDate() + 6 - dn); // Next Saturday
  do {
    a[i--] = i + ' ' + aZ(d.getDate()) +
             '-' + aZ(d.getMonth() + 1) +
             '-' + d.getFullYear() + 
             ' ' + days[d.getDay()];     
    d.setDate(d.getDate() - 1);
  } while (i);
  return a;
}
// Test it
var date = new Date(2012,2,2)
alert( date + 'nn' + getDateArray(date).join('n'));
/*
  Fri Mar 02 2012 00:00:00
  0 27-02-2012 Monday
  1 28-02-2012 Tuesday
  2 29-02-2012 Wednesday
  3 01-03-2012 Thursday
  4 02-03-2012 Friday
  5 03-03-2012 Saturday
*/