我有一个熊猫数据框,如下:
coname1 coname2
Apple [Microsoft, Apple, Google]
Yahoo [American Express, Jet Blue]
Gap Inc [American Eagle, Walmart, Gap Inc]
我想创建一个新列,该列标记Coname1中的字符串是否包含在conames中。因此,从上面的示例中,数据帧现在为:
coname1 coname2 isin
Apple [Microsoft, Apple, Google] True
Yahoo [American Express, Jet Blue] False
Gap Inc [American Eagle, Walmart, Gap Inc] True
设置帧:
df =pd.DataFrame({'coname1':['Apple','Yahoo','Gap Inc'],
'coname2':[['Microsoft', 'Apple', 'Google'],['American Express', 'Jet Blue'],
['American Eagle', 'Walmart', 'Gap Inc']]})
尝试以下操作:
df['isin'] =df.apply(lambda row: row['coname1'] in row['coname2'],axis=1)