Python的替代技术"如果...妖孽...否则"循环超过 1,500 个选项

Question

以下是我正在进行的社区项目的示例代码。

cat1 = 'Engr, Bricklayer, Attendant'
cat2 = 'Programmer, Artist, Engr, Servant'
cat3 = 'Programmer, Typist'

amount = float(input("Enter amount: "))
choice = input("Select Beneficiary: ")

print("-----------------------------------")
if choice == cat1:
    print("Name: EngrnShare: 1/6 (1 cikin 6)nBenefits: N" + str((amount/6) * 1))
    print("-----------------------------------")
    print("Name: BricklayernShare: 1/2 (3 cikin 6)nBenefits: N" + str((amount/6) * 3))
    print("-----------------------------------")
    print("Name: AttendantnShare: 1/3 (2 ciin 6)nBenefits: N" + str((amount/6) * 2))
    print("-----------------------------------")
    print("Jimilla: N" + str(sum([(amount/6) * 1, (amount/6) * 3, (amount/6) * 2])))
elif choice == cat2:
    print("Name: ProgrammernShare: 1/8 (3 cikin 24)nBenefits: N" + str((amount/24) * 3))
    print("-----------------------------------")
    print("Name: ArtistnShare: 1/6 (4 cikin 24)nBenefits: N" + str((amount/24) * 4))
    print("-----------------------------------")
    print("Name: EngrnShare: 1/6 (4 cikin 24)nBenefits: N" + str((amount/24) * 4))
    print("-----------------------------------")
    print("Name: ServantnShare: Ragowa (13 cikin 24)nBenefits: N" + str((amount/24) * 13))
    print("-----------------------------------")
    print("Jimilla: N" + str(sum([(amount/24)*3,(amount/24)*4,(amount/24)*4,(amount/24)*13])))

以下是从用户接收值后的输出：

Enter amount: 2540000
Select Beneficiary: Engr, Bricklayer, Attendant
-----------------------------------
Name: Engr
Share: 1/6 (1 cikin 6)
Benefits: N423333.3333333333
-----------------------------------
Name: Bricklayer
Share: 1/2 (3 cikin 6)
Benefits: N1270000.0
-----------------------------------
Name: Attendant
Share: 1/3 (2 ciin 6)
Benefits: N846666.6666666666
-----------------------------------
Jimilla: N2540000.0
>>> 

您可以看到，我正在使用if ... elif ... else控制语句遍历代码顶部定义的类别中的元素。我必须创建约1,500个不同的类别，其中包括有权获得不同股份的不同元素/受益人的组合。我可以使用任何技术来循环通过选项，而不是使用If ... Elif ... else？

我是Python的新手。上面代码的输出是我想要的，但是使用if ... elif ... else对1,500个类别进行检查会有点单调或忙碌。

我需要您的帮助。

Answer 1

首先，您可以将所有受益人用作格式中的CSV文件

[受益人，分子，dinominator]

如下所示

category.csv内容：

Engr, 1, 6
Bricklayer, 3, 6
Attendant, 2, 6
Programmer, 3, 24
Artist, 4, 24
Engr, 4, 24
Servant, 13, 24

然后将数据转换为字典并相应地操纵。以下代码将给出类似的输出。

import csv
beneMap = {}
with open("category.csv") as f:
    csvFile = csv.reader(f)
    for row in csvFile:
        beneMap[row[0]] = (row[1], row[2])
def getJimilla(beneMap, benef, amount):
    benList = benef.split(', ')
    jimilla = 0
    for name in benList:
        ben = beneMap[name]
        jtemp = amount*int(ben[0])/int(ben[1])
        print("Name: "+name 
              +"nShare: "+ben[0]+"/"+ben[1]+" ("+ben[0]+" cikin "+ben[1]+")"
              +"nBenefits: N" + str(round(jtemp,2))
              +"n-----------------------------------")
        jimilla += jtemp
    print("Jimilla: N"+str(round(jimilla,2)))
amount = float(input("Enter amount: "))
choice = input("Select Beneficiary: ")
print("-----------------------------------")
getJimilla(beneMap, choice, amount)

样本运行：

Enter amount: 2540000
Select Beneficiary: Engr, Bricklayer, Attendant
-----------------------------------
Name: Engr
Share:  4/ 24 ( 4 cikin  24)
Benefits: N423333.33
-----------------------------------
Name: Bricklayer
Share:  3/ 6 ( 3 cikin  6)
Benefits: N1270000.0
-----------------------------------
Name: Attendant
Share:  2/ 6 ( 2 cikin  6)
Benefits: N846666.67
-----------------------------------
Jimilla: N2540000.0

请注意，当给出输入序列时，可以理解该类别，因此在CSV文件中无需携带有关受益人类别的额外信息。