我们正在准备李克特类型刻度。必须只允许受试者按1-9的数字。我们知道ListChenchar,但它压制了整个键盘。我们如何抑制非数字键?
while(1)
ch = GetChar;
if ch == 10 %return is 10 or 13
%terminate
break
else
response=[response ch];
end
end
如果您只想接受按键1-9:
while(1)
ch = GetChar;
if ch == 10 %return is 10 or 13
%terminate
break
elseif (ch>48) & (ch<58) %check if the char is a number 1-9
response=[response ch];
pause(0.1) %delay 100ms to debounce and ensure that we don't count the same character multiple times
end
end
我还添加了一次调试,因此您不会意外地记录单个输入。
PsychToolbox通过RestrictKeysForKbCheck
包含功能,以限制收听特定键。
以下代码限制了1-9的可能输入,加上ESC键:
KbName('UnifyKeyNames'); % use internal naming to support multiple platforms
nums = '123456789';
keynames = mat2cell(nums, 1, ones(length(nums), 1));
keynames(end + 1) = {'ESCAPE'};
RestrictKeysForKbCheck(KbName(keynames));
下面是一个块的微不足道示例:
response = repmat('x', 1, 10); % pre-allocate response, similar to OP example
for ii = 1:10
[~, keycode] = KbWait(); % wait until specific key press
keycode = KbName(keycode); % convert from key code to char
disp(keycode);
if strcmp(keycode, 'ESCAPE')
break;
else
response(ii) = KbName(keycode);
end
WaitSecs(0.2); % debounce
end
RestrictKeysForKbCheck([]); % re-enable all keys