如何在python中传递kwargs到另一个kwargs

Question

def a(**akwargs):
    def b(bkwargs=akwargs):
        # how to not only use akwargs defaultly,but also define bkwargs by
        # myself?
        print bkwargs
    return b

如果我想实现以下功能。我该如何处理上面的代码呢?

>>>a(u='test')()
{'u': test}
>>>a(u='test')(u='test2')
{'u': test2}

Answer 1

你想要什么有点不清楚，但我认为这是诀窍:

def a(**akwargs):
    def b(bkwargs=akwargs, **kwargs):
        # how to not only use akwargs defaultly,but also define bkwargs by
        # myself?
        if not bkwargs:
            bkwargs = kwargs
        else:
            # it depends what you want here (merge or replace?), but probably
            # something like bkwargs.update(kwargs) or kwargs.update(bkwargs)
    return b

Answer 2

将外部函数中的kwargs作为默认值，并更新传递给内部函数的kwargs。

from functools import partial
def outer(**kwargs):
    def inner(**kwargs):
        return(kwargs)
    return partial(inner, **kwargs)

如果没有将kwargs分配给内部函数，则下一个函数使用外部函数中的kwargs。

def outer(**outer_kwargs):
    def inner(**inner_kwargs):
        kwargs = inner_kwargs or outer_kwargs
        return kwargs
    return inner

Answer 3

为什么不这样做呢?

def a(**akwargs):
    def b(**bkwargs):
        allkwargs = {}
        allkwargs.update(akwargs)
        allkwargs.update(bkwargs)
        print allkwargs
    return b

使用来自a的值，但允许您通过传递更多的值给b来覆盖它。所以:

>>> a(u='test')()
{'u': 'test'}
>>> a(u='test')(u='test2')
{'u': 'test2'}