如何扫描，查找和连接到一个开放的wifi AP编程

Question

我正在开发一个应用程序，该应用程序应该自动定期启用wifi，扫描网络，过滤掉开放的网络(不需要通过)，创建一个wificconfiguration对象并使用它连接到该网络。

我读了android开发者的wificationapi。在此基础上，我写了一个代码示例，它确实启用了wifi，扫描网络并将结果保存在一个列表中，看起来像这样:

11-25 16:05:44.191: I/WIFISCAN(12955): List of networks: [SSID: airlive_w, BSSID: 00:4f:62:2c:96:18, capabilities: [WPA-PSK-CCMP][WPA2-PSK-CCMP][WPS], level: -71, frequency: 2432, SSID: Mikynet, BSSID: 00:1e:2a:ed:62:4e, capabilities: [WPA2-PSK-CCMP], level: -72, frequency: 2427, SSID: TP-LINK_Vectra, BSSID: 74:ea:3a:ab:eb:b0, capabilities: [WPA2-PSK-TKIP+CCMP][WPS], level: -73, frequency: 2462, SSID: Nasza Siec- ryby, BSSID: d8:5d:4c:df:60:74, capabilities: [WPA2-PSK-TKIP+CCMP-preauth], level: -88, frequency: 2437, SSID: lanzarote, BSSID: 00:27:19:f7:05:9c, capabilities: [WPA-PSK-TKIP+CCMP][WPA2-PSK-TKIP+CCMP-preauth], level: -89, frequency: 2437, SSID: Alicja, BSSID: 94:44:52:a7:17:02, capabilities: [WPA-PSK-CCMP][WPA2-PSK-CCMP][WPS], level: -89, frequency: 2442, SSID: orangebox, BSSID: 00:1f:f3:f8:ea:0f, capabilities: [WPA2-PSK-CCMP], level: -89, frequency: 2462]

有了这个结果，我怎么知道哪个是打开的(通过自由)?我如何为打开的一个创建wi - fi配置?

下面是WPA-PSK的一个示例wificationconfiguration:

WifiManager wifi = (WifiManager) getSystemService(Context.WIFI_SERVICE);
WifiConfiguration wc = new WifiConfiguration();
// This is must be quoted according to the documentation 
// http://developer.android.com/reference/android/net/wifi/WifiConfiguration.html#SSID
wc.SSID = ""SSIDName"";
wc.preSharedKey  = ""password"";
wc.hiddenSSID = true;
wc.status = WifiConfiguration.Status.ENABLED;        
wc.allowedGroupCiphers.set(WifiConfiguration.GroupCipher.TKIP);
wc.allowedGroupCiphers.set(WifiConfiguration.GroupCipher.CCMP);
wc.allowedKeyManagement.set(WifiConfiguration.KeyMgmt.WPA_PSK);
wc.allowedPairwiseCiphers.set(WifiConfiguration.PairwiseCipher.TKIP);
wc.allowedPairwiseCiphers.set(WifiConfiguration.PairwiseCipher.CCMP);
wc.allowedProtocols.set(WifiConfiguration.Protocol.RSN);
int res = wifi.addNetwork(wc);
Log.d("WifiPreference", "add Network returned " + res );
boolean b = wifi.enableNetwork(res, true);        
Log.d("WifiPreference", "enableNetwork returned " + b );

任何指导将高度赞赏!:)

Answer 1

据我所知，你可能不得不尝试为Wifi服务添加一个开放配置。如果添加一个开放网络失败，它可能需要某种认证协议。

WifiConfiguration wc = new WifiConfiguration();
wc.SSID = "some ssid from the list";
wc.status = WifiConfiguration.Status.ENABLED;
wc.allowedAuthAlgorithms.set(WifiConfiguration.AuthAlgorithm.OPEN);
WifiManager wifi = (WifiManager) getSystemService(Context.WIFI_SERVICE);
int networkId = wifi.addNetwork(wc);
if (networkId == -1) {
    // probably not open
} else {
    // likely open
}

您还可以将此方法与getConfiguredNetworks方法结合使用，以查看是否有任何附近的网络a)先前已连接并且b)是打开的。