使用HTML按钮而不是与Mapbox GL JS的链接切换Geojson图层

Question

我正在在一个网络地图上工作，该网络地图涉及打开和关闭两个Geojson层。我以前使用Mapbox JS来完成此操作，并使用自定义HTML按钮在单击时添加它们，但是使用Mapbox GL JS来实现此问题。我要做的就是使用HTML按钮，而不是附加到创建的CSS菜单的链接：

使用HTML按钮，将两层打开和关闭（显示和隐藏）：

var layers = document.getElementById('menu');
layers.appendChild(link);

我认为我可以将功能绑定到按钮元素，但不能使其正常工作：

document.getElementById("toggle-layer-one").onclick = function() {};

html：

<button data-balloon="Campsite" data-balloon-pos="right" id="toggle-layer-one"></button>

CSS

#toggle-layer-one {
background-image: url("../Assets/Campsite.svg");
background-size: 70px 70px;
height: 70px;
width: 70px;
border-top: 1px solid #fff;
}

JS

map.on('style.load', function () {
map.addSource("sample", {
    type: "geojson",
    data: "https://raw.githubusercontent.com/aarontaveras/Sample-GeoJSON-Data/master/sample.geojson"
});
map.addLayer({
    "id": "sample-point-one",
    "type": "symbol",
    "source": "sample",
    "filter": ["==", "$type", "Point"],
    "layout": {
        "icon-image": "circle-15",
        "icon-size": 1,
        "icon-anchor": "center",
    }
});
map.setFilter('sample-point-one', ['==', 'region', 'Africa']);
map.addLayer({
    "id": "sample-point-two",
    "type": "symbol",
    "source": "sample",
    "filter": ["==", "$type", "Point"],
    "layout": {
        "icon-image": "circle-15",
        "icon-size": 1,
        "icon-anchor": "center",
    }
});
map.setFilter('sample-point-two', ['==', 'region', 'Asia']);
});
// Toggle layers
var toggleableLayerIds = ["sample-point-one", "sample-point-two"];
for (var i = 0; i < toggleableLayerIds.length; i++) {
var id = toggleableLayerIds[i];
var link = document.createElement('a');
link.href = '#';
link.className = 'active';
link.textContent = id;
link.onclick = function (e) {
    var clickedLayer = this.textContent;
    e.preventDefault();
    e.stopPropagation();
    var visibility = map.getLayoutProperty(clickedLayer, 'visibility');
    if (visibility === 'visible') {
        map.setLayoutProperty(clickedLayer, 'visibility', 'none');
        this.className = '';
    } else {
        this.className = 'active';
        map.setLayoutProperty(clickedLayer, 'visibility', 'visible');
    }
};
var layers = document.getElementById('menu');
layers.appendChild(link);
}

谢谢！

Answer 1

我最终弄清楚了。

html：

<a id="test" href="#">TEST</a>

JS：

var toggleLayerId = ["sample-point-one"];
document.getElementById("test").onclick = function (e){
for (var index in toggleLayerId) {
    var clickedLayer = toggleLayerId[index];
    e.preventDefault();
    e.stopPropagation();
    var visibility = map.getLayoutProperty(clickedLayer, 'visibility');
    if (visibility === 'visible') {
        map.setLayoutProperty(clickedLayer, 'visibility', 'none');
        this.className = '';
    } else {
        this.className = 'active';
        map.setLayoutProperty(clickedLayer, 'visibility', 'visible');
    }
}
};