如何循环动态延迟的 SKActions 序列

Question

我需要运行未知数量的 SKAction 序列(来自字典数组(，这些序列在循环中动态创建和偏移，延迟随着循环而增加。 循环的打印输出应按以下顺序显示

show line 5
hiding everything
show line 6
hiding everything
show line 2
hiding everything

要获得此功能，我使用此代码

func display(winningLines: [Int : AnyObject]) {
    var delay = 0.0
    var actions = [SKAction]()
    let hideAction = SKAction.run {
        print("hiding everything")
    }
    for winningLine in winningLines {
        let displayAction = SKAction.run {
            print("line (winningLine.key)")
        }
        let wait = SKAction.wait(forDuration: delay)            
        var action: SKAction!
        //repeatForever = true
        if !repeatForever {
             action = SKAction.sequence([wait, displayAction, SKAction.wait(forDuration: 1.0), hideAction])
        }
        else {
            let seq = SKAction.sequence([wait, displayAction, SKAction.wait(forDuration: 1.0), hideAction])
            action = SKAction.repeatForever(seq)
        }
        self.run(action)
        delay += 1.0
    }
}

如果序列只需要发生一次，而不是按预期输出，但是有时我需要序列永远重复(直到用户停止操作(。在动作周围永远重复是行不通的，因为它会重复每个单独的序列并弄乱顺序。第一个序列将每 1 秒重复一次，第二个序列将每 2 秒重复一次......等。

关于如何让它永远正确循环的任何建议？

line 5
hiding everything
line 5
line 6
hiding everything
line 5
hiding everything
line 2
hiding everything
line 5
line 6
hiding everything
hiding everything
line 5
hiding everything
hiding everything
line 5
line 6
line 2
hiding everything
line 5
hiding everything
hiding everything

我还尝试将这些操作附加到 SKActions 数组并在最后循环访问它们，但它不起作用

var actions = [SKAction]()

。

actions.append(action)
for action in actions {
    self.run(action)
}

Answer 1

如果您唯一关心的是永远重复未知数量的序列，您可以执行以下操作：

• 创建所有必需的序列
• 将它们放在另一个序列中
• 永远循环

例如，此代码将创建四个框，并将按

顺序将淡入/淡出(显示操作/隐藏代码中的操作(应用于每个框，并将永远重复此操作：

import SpriteKit
class GameScene: SKScene {
var boxes:[SKSpriteNode] = []
override func didMove(to view: SKView) {
    let distance:CGFloat = 10
    for i in 0...3 {
        let box = SKSpriteNode(color: .purple, size: CGSize(width: 50, height: 50))
        box.name = String(i) //name == index
        box.position.x = CGFloat(i) * (box.size.width + distance)
        box.alpha = 0.0
        addChild(box)
        boxes.append(box)
    }
}
override func touchesBegan(_ touches: Set<UITouch>, with event: UIEvent?) {
    var actions:[SKAction] = []
    let action = SKAction.sequence([
        SKAction.fadeIn(withDuration: TimeInterval(1)),
        SKAction.fadeOut(withDuration: 0),
    ])
    for index in 0...boxes.count {
        let sequence = SKAction.sequence([
            SKAction.run(action, onChildWithName: String(index)),
            SKAction.wait(forDuration: 1)
        ])
        actions.append(sequence)
    }
    self.run(SKAction.repeatForever(SKAction.sequence(actions)))
}
}