如何将 3D 数组写入文本文件



>我得到了这样的数组:

[[-3.75536609e+00  9.41899478e-01  1.59805989e+00 -8.97728577e-02
-3.67324662e+00  2.85971731e-01]
[-1.48593640e+00  6.56555116e-01  6.41966641e-01 -2.62360811e-01
-4.66498184e+00 -8.62938017e-02]
[ 7.05197873e-03 -4.12116805e-03 -1.30933505e-02  5.76611329e-03
-6.51661423e-04 -9.73143987e-03]
...
[ 7.28487849e-01 -2.02445209e-01 -1.56245055e-02 -1.48709917e+00
-4.94436502e+00 -1.88474905e+00]
[ 6.85976565e-01 -1.20424531e-01 -2.20480785e-01 -1.23380101e+00
-3.60452390e+00 -1.54651344e+00]
[ 1.47314686e-02  1.42228836e-02 -1.20135369e-02 -4.32784623e-03
-8.07471294e-03  2.29109559e-04]]
[-0.6025902  -0.31237862 -1.2150506   3.072987   -1.3560013  -1.0883616 ]

我希望能够将此数组写入文本文件。每个元素都应逐行打印。例如,第一个可能看起来像这样

-3.75536609e+00 
9.41899478e-01 
1.59805989e+00 
-8.97728577e-02
-3.67324662e+00 
2.85971731e-01

我该怎么做?

如果这些是numpy数组,则可以将np.savetxtdelimiter='n'一起使用,并通过数组进行枚举:

给定数组x

>>> x
array([[-3.75536609e+00,  9.41899478e-01,  1.59805989e+00,
-8.97728577e-02, -3.67324662e+00,  2.85971731e-01],
[-1.48593640e+00,  6.56555116e-01,  6.41966641e-01,
-2.62360811e-01, -4.66498184e+00, -8.62938017e-02],
[ 7.05197873e-03, -4.12116805e-03, -1.30933505e-02,
5.76611329e-03, -6.51661423e-04, -9.73143987e-03]])

用:

[np.savetxt(f'array{n}.txt',i,delimiter='n') for n,i in enumerate(x)]

您将获得 3 个文本文件:

array0.txt将是:

-3.755366089999999879e+00
9.418994779999999567e-01
1.598059890000000038e+00
-8.977285769999999998e-02
-3.673246620000000018e+00
2.859717310000000068e-01

等。。。

[编辑]看来我误解了你的问题。如果您只需要一个 txt 文件,请使用:

np.savetxt('array.txt', x.flatten(), delimiter='n')

这将给array.txt

-3.755366089999999879e+00
9.418994779999999567e-01
1.598059890000000038e+00
-8.977285769999999998e-02
-3.673246620000000018e+00
2.859717310000000068e-01
-1.485936399999999935e+00
6.565551160000000497e-01
6.419666410000000045e-01
-2.623608110000000271e-01
-4.664981840000000268e+00
-8.629380170000000572e-02
7.051978730000000098e-03
-4.121168050000000374e-03
-1.309335049999999986e-02
5.766113290000000370e-03
-6.516614230000000382e-04
-9.731439870000000575e-03

来自此解决方案

def flatten(l):
for el in l:
if isinstance(el, collections.Iterable) and not isinstance(el, (str, bytes)):
yield from flatten(el)
else:
yield el

创建一个简单的列表。然后将其转储到文件:

with open(outfile) as f:
f.write("n".join(flatlist))

最新更新