我试图在具有以下结构的spock框架下执行测试
class UserServiceSpec extends Specification{
ModelMapper modelMapper = Stub(ModelMapper.class)
UserRepository userRepository=Mock(UserRepository.class)
UserService userService
def setup(){
userService= new UserServiceImpl(userRepository,modelMapper)
}
def "find user by email"(){
given: "Creates a constant with an existing email"
def constant ="juan@rodriguez.com"
when: "Calling the method findUserByEmail"
def response= userService.findUserByEmail(constant)
then:"Comparing the response result with the constant"
response.getEmail()==constant
}
}
然而，当我尝试获取response.getEmail((的值时，结果是一个null对象，它应该获得与"相同的参数；常数"；，错误是：
Cannot invoke method getEmail() on null object
UserService的代码结构和实现是：
public interface UserService {
UserModel findUserByEmail(String email);
}
UserService的实现是：
@Service
@Qualifier("userDetailsService")
public class UserServiceImpl implements UserService, UserDetailsService {
private final UserRepository userRepository;
private final ModelMapper modelMapper;
public UserServiceImpl(UserRepository userRepository,ModelMapper modelMapper){
this.userRepository= userRepository;
this.modelMapper= modelMapper;
}
}
然而，如果我用相同的方法从控制器(spring项目(调用Service，我会得到一个带有其参数的对象。如何修复这个spock测试？
- 我试过"自动连线"；而不是初始化为UserServiceImpl，但它不起作用
- 我试着不嘲笑映射器和存储库，但仍然得到了相同的null对象
您没有指定与mockUserRepository的任何交互，因此Spock从您对其进行的任何方法调用中返回null。假设您的存储库是一个普通的存储库，可以这样说：
then:
userRepository.findByEmail(constant) >> { c -> new UserEntity(email: c, ...) }
constant == response.email // expected value comes first, and you can use Groovy property syntax