比较2对象，并以递归方式列出缺少键和值更改

Question

想要比较2 out和miss out丢失的字段和值的递归变化

obj1 = {
"val1": "test",
"stream": {
"key": true,
"value": false
},
"val2": "test",
"val3": "test",
}
obj2 = {
"val1": "test",
"stream": {
"key": false,
"value": false
}
}

我需要2个输出，如下

output1 = {
"val2": "test",
"val3": "test"
}
output2 = {
"stream": {
"key": true
}
}

Answer 1

它是深度比较对象的某个版本。我将两个输出合并为一个函数，因为它们都表示不同的属性。

var obj1 = {
"val1": "test",
"stream": {
"key": true,
"value": false
},
"val2": "test",
"val3": "test",
}
var obj2 = {
"val1": "test",
"stream": {
"key": false,
"value": false
}
}

function diffCompare(obj1, obj2) {
var list = [];
function is_obj(obj) {
return typeof obj === 'object' && obj !== null
}
function iterate(obj1, obj2, path) {
path = path || []
Object.keys(obj1).forEach(function(key) {
if (obj1[key] != obj2[key]) {
if (is_obj(obj1[key]) && is_obj(obj2[key])) {
iterate(obj1[key], obj2[key], path.concat(key))
} else {
list.push({
path: path.concat(key),
value: obj1[key]
})
}
}
})
}
iterate(obj1, obj2)
// console.log(list)
// building result object:
var result = list.reduce(function(agg, {path, value}) {
var pointer = agg;
while (path.length) {
var part = path.shift();
pointer[part] = pointer[part] || {}
if (path.length) {
pointer = pointer[part]
} else {
pointer[part] = value;
}
}
return agg;
}, {});

return result;
}
console.log(diffCompare(obj1, obj2))

.as-console-wrapper {
max-height: 100% !important
}