在python中查找单词的位置

Question

假设我有这个代码

text=['Whatsapp app open']

def check(i,text):
if i!=-1:
return i
res=[]
for t in text:
i=t.find('app')
f=check(i,t)
res.append(t[0:f])
print(res)

我希望输出是Whatsapp，而不仅仅是Whats。有没有任何函数可以将整个字符串作为一个整体，并返回索引，以便我可以打印Whatsapp而不是Whats？

Answer 1

您应该将文本拆分为单词列表，并使用for-循环检查if "app" in word:

sentences = ['Whatsapp app open', 'Instagram app open']

for text in sentences:
res = []
for word in text.split(' '):
#if 'app' in word.lower():
if 'app' in word:
res.append(word)
print(text, res)

结果：

Whatsapp app open ['Whatsapp', 'app']
Instagram app open ['app']

与列表理解相同

for text in sentences:

res = [word for word in text.split(' ') if 'app' in word]
print(text, res)

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或者您应该使用regex

import re
sentences = ['Whatsapp app open', 'Instagram app open']
for text in sentences:

res = re.findall('[^ ]*app[^ ]*', text)
print(text, res)

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对于更复杂的东西，您可能需要Natural Language Processing，即模块nltk