我有一个存储夏令时和非夏令时记录的表
CREATE TABLE #tmp
(
ID int,
IntervalName nvarchar(100),
StartDate datetime,
EndDate Datetime,
offset numeric(5, 2)
)
INSERT INTO #tmp
VALUES (1, 'EDT', '2022-03-13 07:00:00.000', '2022-11-06 06:00:00.000',-4.00)
INSERT INTO #tmp
VALUES (2, 'EST', '2022-11-06 06:00:00.000', '2023-03-12 07:00:00.000', -5.00)
我有我的事务表,Date
列在GMT时区。
ID DatetimeGMT DatetimeLocal
---------------------------------------------------------
1 2022-11-05 07:00:00.000 2022-11-05 03:00:00.000
2 2022-11-10 06:00:00.000 2023-11-10 01:00:00.000
现在我的DatetimeLocal
列正在计算基于DatetimeGMT
列的偏移小时。
ID = 1
所在行偏移量为-4,ID = 2
所在行偏移量为-5。
有什么建议我们可以做到这一点吗?
如果所有的偏移量都存储在这样的表中,那么您只需要JOIN就可以找到正确的偏移量
如
drop table if exists #tmp
drop table if exists #tran
go
CREATE TABLE #tmp
(
ID int,
IntervalName nvarchar(100),
StartDate datetime,
EndDate Datetime,
offset numeric(5, 2)
)
INSERT INTO #tmp
VALUES (1, 'EDT', '2022-03-13 07:00:00.000', '2022-11-06 06:00:00.000',-4.00)
INSERT INTO #tmp
VALUES (2, 'EST', '2022-11-06 06:00:00.000', '2023-03-12 07:00:00.000', -5.00)
create table #tran(id int primary key, DateTimeUTC datetime)
insert into #tran(id,DateTimeUTC) values (1,'2022-11-05 07:00:00.000'),(2,'2022-11-10 06:00:00.000')
select t.id, t.DateTimeUTC, dateadd(hour,offset,t.DateTimeUTC) DateTimeLocal, tz.offset
from #tran t
join #tmp tz
on t.DateTimeUTC >= tz.StartDate
and t.DateTimeUTC < tz.EndDate
输出id DateTimeUTC DateTimeLocal offset
----------- ----------------------- ----------------------- ---------------------------------------
1 2022-11-05 07:00:00.000 2022-11-05 03:00:00.000 -4.00
2 2022-11-10 06:00:00.000 2022-11-10 01:00:00.000 -5.00
SQL Server 2016及以后版本内置了偏移量,所以你可以编写像
这样的查询select t.id,
t.DateTimeUTC,
cast(t.DateTimeUTC at time zone 'UTC' at time zone 'EASTERN STANDARD TIME' as datetime) DateTimeLocal
from #tran t