我正在学习使用数组。
下面的代码是用户将输入一个范围,然后检查范围的值"abc"在每一行中,1然后将其添加到数组中,然后使用列号的数组值删除整个列,下面的代码有一个错误,说类型不匹配,说x为空。
Option Explicit
Sub delete_column()
Dim arr As Variant, x As Integer, myrange As String, rng As Range, cell,
item as Variant
Set arr = CreateObject("System.Collections.ArrayList")
myrange = InputBox("Please enter the range:", "Range")
If myrange = "" Then Exit Sub
Set rng = Range(myrange)
For Each cell In rng
If cell.Value = "abc" Then arr.Add cell.Column
Next cell
For x = UBound(arr) To LBound(arr)
Cells(1, arr(x)).EntireColumn.Delete
Next x
End Sub
我想不出如何修复这个错误。当我将鼠标悬停在x上时,错误显示类型不匹配后,它显示为空。当我将鼠标悬停在arr(x)上时,它有正确的列号。
我用For x = UBound(arr) To LBound(arr) Step -1
still error
我在下面使用,但它只删除了一些列,而不是所有的值都是abc。
对于arr中的每个项目.EntireColumn.Delete细胞(1项)下一个项目
您不能在变体上使用Ubound()
和Lbound()
方法。如果要使用数组,则必须用括号声明arr
。下面我将arr声明为一个整数数组。
Option Explicit
Sub delete_column()
Dim arr() As Integer, x As Integer, myrange As String, rng As Range, item As Variant, cell
myrange = InputBox("Please enter the range:", "Range")
If myrange = "" Then
Exit Sub
End If
Set rng = Range(myrange)
For Each cell In rng
If cell.Value = "abc" Then
If (Not Not arr) = 0 Then'check if arr is not dimensioned
ReDim arr(0) 'dimension the array
arr(UBound(arr)) = cell.Column
Else
ReDim Preserve arr(UBound(arr) + 1)'expand the array by 1
arr(UBound(arr)) = cell.Column
End If
End If
Next cell
For x = UBound(arr) To LBound(arr) Step -1
Cells(1, arr(x)).EntireColumn.Delete
Next x
End Sub
我使用。count找到了下面的解决方案,我不知道为什么使用inbound和lbound迭代不起作用
"
Option Explicit
Sub delete_column()
Dim arr As Variant, x As Integer, myrange As String, rng As Range, cell
Set arr = CreateObject("System.Collections.ArrayList")
myrange = InputBox("Please enter the range:", "Range")
If myrange = "" Then Exit Sub
Set rng = Range(myrange)
For Each cell In rng
If cell.Value = "abc" Then arr.Add cell.Column
Next cell
For x = arr.Count - 1 To 0 Step -1
Cells(1, arr(x)).EntireColumn.Delete
Next
End Sub
"