Pydantic数据类在VSCode中的智能感知错误

Question

我在继承的pydantic数据类上收到一个智能感知错误。我能够在两个操作系统上复制这个，一个在VSCode中，另一个在pycharm中。

你可以用下面的代码片段复制智能感知错误:

from abc import ABC, abstractmethod
from pydantic import BaseModel, dataclasses
from typing import List
# python --version -> Python 3.10.2
# pydantic=1.9.0
# Running on MacOS Monterey 12.3.1

@dataclasses.dataclass(frozen=True, eq=True)
class PersonABC(ABC):
name: str
@abstractmethod
def print_bio(self):
pass
@dataclasses.dataclass(frozen=True, eq=True)
class Jeff(PersonABC):
age: int
def print_bio(self):
print(f"{self.name}: {self.age}")     # In VScode, self.name is not registered as a known variable:
# `Cannot access member "name" for type "Jeff"
# Member "name" is unknownPylancereportGeneralTypeIssues`
class Family(BaseModel):
person: List[PersonABC]

jeff = Jeff(name="Jeff Gruenbaum", age=93)
print(Family(person=[jeff]))

错误发生在实现的print_bio函数中。完整的错误在上面的评论中。有没有办法解决这个问题，重新获得智能感?

Answer 1

我可以通过继承BaseModel来解决这个问题，而不是使用pydantic. datacclasses .dataclass。我相信这是pydantic数据类或Pylance的错误，但使用BaseModel是一个可行的解决方案。

from abc import ABC, abstractmethod
from typing import List
from pydantic import BaseModel
# python --version -> Python 3.10.2
# pydantic=1.9.0
# Running on MacOS Monterey 12.3.1

class PersonABC(ABC, BaseModel):
name: str
@abstractmethod
def print_bio(self):
pass
class Jeff(PersonABC):
age: int
def print_bio(self):
print(f"{self.name}: {self.age}")     # Now the intellisense error does not appear.
class Family(BaseModel):
person: List[PersonABC]

jeff = Jeff(name="Jeff Gruenbaum", age=93)
print(Family(person=[jeff]))