C语言 如何读取txt文件到数组并按升序排序?

Question

我有一个包含10000个密码的txt文件。我正试着按长度对密码进行排序。下面是我的函数:

void bubbleSortASC(){
int n = 9999;
int i,j ;
char pw[n];
char temp;
FILE* fp;
fp = fopen("C:\Users\inanm\Desktop\project-work-2018555459\10-million-password-list-top\10000.txt", "r");
//fgets(pw, n , fp);
while(!feof(fp)){
fgets(pw, n , fp);
//printf("%s",pw);
}
for(i = 0; i < n-1;i++) {
for(j = i+1; j < n; j++){
if(strlen(pw[i]) > strlen(pw[j])){
strcpy(temp,pw[i]);
strcpy(pw[i],pw[j]);
strcpy(pw[j],temp);
}
}
}
fclose(fp);
printf("Ascending order of first 10 passwords are : n");
for (i = 0; i < 10; i++){
printf("%s ", pw[i]);
}
printf("n");

}

我没有错误，但是输出是空的。你能帮我找出问题吗?

Answer 1

这样做

void bubbleSortASC() {
const int lines = 9999;     //< number of words in the file
const int max_width = 128;  //< max width of a word
char pw[lines][max_width];  //< array of words
FILE* fp;
fp = fopen("words.txt", "r");
int curr = 0;
while (!feof(fp)) {
fgets(pw[curr++], max_width, fp);
}
fclose(fp);
char* sorted[lines];        //< array of char* will be in a sorted order
for (int i = 0; i < lines; i++) sorted[i] = pw[i];
// the bubble sort
for (int i = 0; i < lines - 1; i++) {
for (int j = 0; j < lines - i - 1; j++) {
if (strlen(sorted[j]) > strlen(sorted[j+1])) {
char* tmp = sorted[j];
sorted[j] = sorted[j+1];
sorted[j+1] = tmp;
}
}
}
printf("Ascending order of first 10 passwords are : n");
for (int i = 0; i < 10; i++) {
printf("%s", sorted[i]);
}
printf("n");
}