我无法让脚本动态打印输出

Question

运行以下脚本时，没有打印任何内容，但当我按ctrl+c并结束任务时，打印完整的输出。我想使它在一种方式，每一行的列表是动态打印的，因为脚本本身正在运行我要运行的函数是…'

`def passive_scan(interface):
result=[]
ip=[]
packets = []
mode="p"
sniff(iface="eth0", prn=filter_packets(packets),timeout= 10000)
for p in packets:
if p[0]["ARP"].op==2:
src_mac=p[0]["ARP"].hwsrc
src_ip=p[0]["ARP"].psrc
ip.append(src_ip)
dict={"mac":src_mac,"ip":src_ip}
result.append(dict)
for client in result:
client["count"]=countOf(ip,client["ip"])
print_result(result,mode)`

'我使用的输出打印函数是.....

```
`print("Interface: "+interface+"ttMode: PassivetttFound "+str(len(list))+" hosts")        
print("----------------------------------------------------------------------------")
print("MACttttIPtttHost Activity")
print("----------------------------------------------------------------------------")
for client in list:
print(client["mac"] + "tt" + client["ip"]+"tt"+str(client["count"]))`
```
```
`

i was able to properly format the output but to get that to print i have to end the task than only it prints

the required output should look like..
[enter image description here](https://i.stack.imgur.com/4g14d.png)

Answer 1

这是sniff()的预期行为，它是一个阻塞函数。

"sniff()函数监听无限时间，直到用户中断。">

你应该使用AsyncSniffer: https://scapy.readthedocs.io/en/latest/usage.html#asynchronous-sniffing