带有python和tkinter问题的计算器

Question

我能够通过相等功能添加2个数字，但我不知道如何根据单击的按钮更改使用的操作符。

但是由于某些原因，它不能添加十进制数。

也有几个错误我想知道。

来自按钮的错误消息:

Assigning result of a function call, where the function has no return pylint(assignment-from-no-return)

形象from tkinter import *错误:

Unused import enum from wildcard importpylint(unused-wildcard-import)

calculator.py

from tkinter import *
root = Tk()
root.title("Calculator")
#Input box
e = Entry(root, width=70, borderwidth=5)
e.grid(row=0, column=0, columnspan=4, padx=10, pady=10)
def btnclick(number):
current = e.get()
e.delete(0, END)
e.insert(0, str(current) + str(number))
def c():
e.delete(0, END)
def add():
firstnum = e.get()
global fnum
fnum = int(firstnum)
e.delete(0, END)
def sub():
return
def div():
return
def x():
return
def eq():
snum = e.get()
e.delete(0, END)
e.insert(0, fnum + int(snum))
def dec():
current = e.get()
e.delete(0, END)
e.insert(0, str(current) + ".")

#Buttons
n1 = Button(root, text="1", padx=40, pady=20, command=lambda: btnclick(1)).grid(row=3, column=0)
n2 = Button(root, text="2", padx=40, pady=20, command=lambda: btnclick(2)).grid(row=3, column=1)
n3 = Button(root, text="3", padx=40, pady=20, command=lambda: btnclick(3)).grid(row=3, column=2)
n4 = Button(root, text="4", padx=40, pady=20, command=lambda: btnclick(4)).grid(row=2, column=0)
n5 = Button(root, text="5", padx=40, pady=20, command=lambda: btnclick(5)).grid(row=2, column=1)
n6 = Button(root, text="6", padx=40, pady=20, command=lambda: btnclick(6)).grid(row=2, column=2)
n7 = Button(root, text="7", padx=40, pady=20, command=lambda: btnclick(7)).grid(row=1, column=0)
n8 = Button(root, text="8", padx=40, pady=20, command=lambda: btnclick(8)).grid(row=1, column=1)
n9 = Button(root, text="9", padx=40, pady=20, command=lambda: btnclick(9)).grid(row=1, column=2)
n0 = Button(root, text="0", padx=40, pady=20, command=lambda: btnclick(0)).grid(row=4, column=0)
add = Button(root, text="+", padx=39, pady=20, command=add).grid(row=4, column=3)
c = Button(root, text="C", padx=40, pady=20, command=c).grid(row=4, column=2)
sub = Button(root, text="-", padx=39, pady=20, command=sub).grid(row=3, column=3)
x = Button(root, text="x", padx=40, pady=20, command=x).grid(row=2, column=3)
div = Button(root, text="/", padx=39, pady=20, command=div).grid(row=1, column=3)
eq = Button(root, text="=", padx=220, pady=20, command=eq).grid(row=5, column=0, columnspan=4)
dec = Button(root, text=".", padx=39, pady=20, command=dec).grid(row=4, column=1)
root.mainloop()

Answer 1

但是由于某些原因，它不能添加十进制数。

这是因为你在做这个:

fnum = int(firstnum)

你告诉它firstnum是一个整数。试一试:

fnum = float(firstnum)

但是我不知道如何根据你点击的按钮来改变使用的操作符

有很多方法可以给它蒙皮，但一个简单的方法是声明一个全局变量operator，并为它分配一个代表所单击操作的值。

例如:

def x():
operator = 'multiplication'
return

然后在你的相等函数中:

def eq():
snum = float(e.get())
e.delete(0, END)
result = 0
if operator == "addition":
result = fnum + snum
elif operator == "multiplication":
result = fnum * snum
# .... etc, etc.... 
e.insert(0, result)