如何在Symfony EasyAdmin3中创建数据验证系统

Question

要放入上下文中，有一个编辑器可以根据他的id修改他的信息，并且他的信息必须由管理员验证，然后才能持久存在数据库。

我想创建一个临时表来存储编辑器将修改的信息，管理员可以通过EasyAdmin的接口访问他的信息，然后管理员一旦验证了信息，它就会保存在原始表中。

我没有在文档中找到恢复编辑页面形式信息的方法。

我加入了我想要瞄准的crud控制器：

类OperaterCrudController扩展AbstractCrudContrler｛

private $crudUrlGenerator;
private $adminContextProvider;
public function __construct(AdminUrlGenerator $adminUrlGenerator, AdminContextProvider $adminContextProvider)
{
$this->adminUrlGenerator = $adminUrlGenerator;
$this->adminContextProvider = $adminContextProvider;
}
public static function getEntityFqcn(): string
{
return Operateur::class;
}
public function configureFields(string $pageName): iterable
{
return [
IdField::new('id')->hideOnForm(),
TextField::new('name', 'Nom'),
TextEditorField::new('description', 'Description')->hideOnIndex(),
TextareaField::new('address', 'Adresse'),
TextField::new('city', 'Ville')->hideOnIndex(),
TextField::new('postal_code', 'Code Postal')->hideOnIndex(),
TextField::new('email', 'Email'),
TelephoneField::new('phone', 'Téléphone'),
UrlField::new('website', 'Site Web')->hideOnIndex(),
TextEditorField::new('opening_hours', 'Horaires d'Ouverture'),
NumberField::new('latitude', 'Latitude')->hideOnIndex()->setNumDecimals(15),
NumberField::new('longitude', 'Longitude')->hideOnIndex()->setNumDecimals(15),
TextField::new('slug', 'Slug')->hideOnIndex()->setPermission('ROLE_ADMIN'),
DateTimeField::new('created_at', 'Date Création')->onlyOnIndex(),
DateTimeField::new('updated_at', 'Date Modification')->onlyOnIndex(),
AssociationField::new('thematiques', 'Thématiques')
];
}
public function configureActions(Actions $actions): Actions
{
$batchAction = Action::new('approve', 'Approuver', 'fa fa-user-check')
->linkToUrl('approveOperators');
$updateOperator = Action::new('update', 'Enregistrer les modifications', 'fa fa-save')
->linkToCrudAction('saveOperator');

if($this->isGranted('ROLE_ADMIN')){
return $actions
->add(Crud::PAGE_INDEX, $batchAction)
->add(Crud:: PAGE_INDEX, Action::DETAIL)
->setPermission(Action::DELETE, 'ROLE_ADMIN')
->setPermission(Action::NEW, 'ROLE_ADMIN')
->setPermission(Action::EDIT, 'ROLE_ADMIN')
->setPermission($batchAction, 'ROLE_ADMIN');
}
if($this->isGranted('ROLE_EDITOR')){
return $actions
->add(Crud:: PAGE_INDEX, Action::DETAIL)
->add(Crud::PAGE_EDIT, $updateOperator)
->setPermission(Action::DELETE, 'ROLE_ADMIN')
->setPermission(Action::NEW, 'ROLE_ADMIN')
->setPermission($updateOperator, 'ROLE_EDITOR')
->disable( Action::SAVE_AND_RETURN, Action::SAVE_AND_CONTINUE);
}

}
public function approveOperators(): Response{
$this->addFlash('notice', '<span style="color: green"><i class="fa fa-check"></i>Modification effecuté </span>');
$url = $this->adminUrlGenerator
->setAction(Action::INDEX)
->generateUrl();

return $this->redirect($url);

}

public function saveOperator(){
//$this->addFlash('notice', '<span style="color: green"><i class="fa fa-check"></i>Modification pris en compte ! </span>');
//Create my own save button in page edit
}

public function configureCrud(Crud $crud): Crud
{
return $crud
->setEntityPermission('ROLE_EDITOR');
}

public function createIndexQueryBuilder(SearchDto $searchDto, EntityDto $entityDto, FieldCollection $fields, FilterCollection $filters): QueryBuilder
{
$response = parent::createIndexQueryBuilder($searchDto, $entityDto, $fields, $filters);
if(!$this->isGranted('ROLE_ADMIN')){
$response->where('entity.id = :id');
$response->setParameter('id', $this->getUser()->getOperateur());
}

return $response;
}
public function updateEntity(EntityManagerInterface $entityManager, $entityInstance): void
{
parent::updateEntity($entityManager, $entityInstance); // TODO: Change the autogenerated stub
}

感谢您阅读

Answer 1

您应该使用BeforeEntityPersistedEvent:：class

它将在数据库中持久化元素之前自动触发

class EasyAdminSubscriber extends AbstractController implements EventSubscriberInterface
{
public function __construct( )
{
}
public static function getSubscribedEvents(){
return [
BeforeEntityPersistedEvent::class => ['functionName']
];
}
public function functionName(BeforeEntityPersistedEvent $event){
$entity=$event->getEntityInstance();
$user = $this->getUser();
$userRole = $user->getRole();
$check = $this->checkRole($userRole);
if ($entity instanceof yourEntity && $check== true) {

//Do your magic with changing the value you want in the table you
}
}

}

很抱歉没有评论，我没有足够的声誉，所以我在那里回答。