如何在Python中比较和提取两个字典项中的数据

Question

我想通过比较python中的两个dict项来获取数据：

格言1:

rawdata = {
"node1":["id1",["set1a"]],
"node2":["id2",["set1b"]]
}

格言2:

subdata = {
"info1":["set1a","id1","firstset","firstsection"]
"info2":["set1b","id2","secondset","secondsection"]
}

可以看出，原始数据具有子数据值，但没有完整的信息。我想将dict1与dict2进行比较，以获得完整的详细信息，并将输出打印到另一个字典中，如：

"node1":"id1","set1a","firstset","firsstsection",
"node2":"id2","set1b","secondset","secondsection"

通过使用prettytable，我想以表格格式打印从最终字典中提取的信息。有人能帮我解决这个问题吗。

Answer 1

这可以通过dict理解来完成，但为了可读性，让我们在循环中进行：(

for rdk, rdv in rawdata.items():
sdv = next((x for x in subdata.values() if x[1] == rdv[0]))
outd[rdk] = [sdv[1], sdv[0], sdv[2], sdv[3]]

Answer 2

我试图让它更通用：

from pprint import pprint
rawdata = {
"node1": ["id1", ["set1a"]],
"node2": ["id2", ["set1b"]]
}
subdata = {
"info1": ["set1a", "id1", "firstset", "firstsection"],
"info2": ["set1b", "id2", "secondset", "secondsection"]
}
res = {}
for k, v in rawdata.items():
# retrieve the ID
id_ = v[0]

# Check that in 'subdata'
for k1, v1 in subdata.items():
if id_ in v1:

# Because in next line we want to get all of 'subdata' values all together.
v1.remove(id_)
res[k] = (id_, *v1)

# Make subsequent searches efficient by not researching same keys  
del subdata[k1]
break
pprint(res)

输出：

{'node1': ('id1', 'set1a', 'firstset', 'firstsection'),
'node2': ('id2', 'set1b', 'secondset', 'secondsection')}