Django:如何将两个对象列表合并为每五个元素一个列表

Question

我正在尝试制作一个帖子列表，其中每五个帖子都是广告帖子，所以我想制作一个列表，其中第五个元素都来自广告列表。

我从这个答案中尝试了一些东西https://stackoverflow.com/a/34692876/14790632

将这些对象列表分配到一个列表中，我做错了什么

views.py:

def home(request, pk):
#i tried this
#post_list = []
#ad_list = []
#for p in Post.objects.all():
#post_list.append(p.Post) 
#for a in Ads.objects.all():
#ad_list.append(p.Ads)
#and i have tried this below
post_list = Post.objects.all()
ad_list =  Ads.objects.all()
n = 5
iter1 = iter(post_list)
post_ad_list = []
for x in ad_list:
post_ad_list.extend([next(iter1) for _ in range(n - 1)])
post_ad_list.append(x)
post_ad_list.extend(iter1)
context = {
'posts': post_ad_list,
}
return render(request, 'new.html', context)

models.py:

class Ads(models.Model):
post = models.ForeignKey(Post, on_delete=models.CASCADE, null=True)

编辑：从答案中实现后，我现在得到的是帖子，但不是广告帖子。我想这是因为我正在使用Ads.objects.all((，但我应该把它改成什么？

Answer 1

你正朝着正确的方向前进，试试这个：

def home(request, pk):
post_list = Post.objects.all()
ad_list =  Ads.objects.all()
offset = 4
iter1 = iter(post_list)
post_start = 0
post_ad_list = []
for x in ad_list:
post_ad_list.extend(post_list[post_start:post_start + offset])
post_ad_list.append(x)
post_start += offset
context = {
'posts': post_ad_list,
}
return render(request, 'new.html', context)

请注意，循环后无需再次添加帖子

Answer 2

您可以执行此

def home(request, pk):
#i tried this
#post_list = []
#ad_list = []
#for p in Post.objects.all():
#post_list.append(p.Post) 
#for a in Ads.objects.all():
#ad_list.append(p.Ads)
#and i have tried this below
post_list = Post.objects.all()
ad_list =  Ads.objects.all()
n = 5
iter1 = iter(post_list)
post_ad_list = []
for x in ad_list:
# you select one
# this output only element 5
post_ad_list.extend(post_list[4:5])
post_ad_list.append(x)
# or this if you using this => every 5 data will be retrieved => output: [5,10,15,20]
for i in len(post_list):
if not i % n:
post_ad_list.extend(post_list[i-1:i])
post_ad_list.append(x)

context = {
'posts': post_ad_list,
}
return render(request, 'new.html', context)