匹配/合并具有关系的两个数据阵列的最简单方法是什么

Question

假设我有两个用于带票事件的数据数组。一个是与会者：

[
{name: 'Jack', ticket_code: 'iGh4rT'},
{name: 'Lisa', ticket_code: 'it1ErB'}
]

另一种是门票：

[
{code: 'iGh4rT', name: 'General Admission'},
{code: 'it1ErB', name: 'VIP'}
]

现在说我想显示这样的表格：

名称	Ticket名称
Jack	普通入院
Lisa	VIP

您可以将其中一个数组作为对象，并将代码作为该对象的键，然后将另一个数组映射为所需数据和该对象以前存储的数据。

const
attendees = [{ name: 'Jack', ticket_code: 'iGh4rT' }, { name: 'Lisa', ticket_code: 'it1ErB' }],
tickets = [{ code: 'iGh4rT', name: 'General Admission' }, { code: 'it1ErB', name: 'VIP' }],
ticketsByCode = Object.fromEntries(tickets.map(o => [o.code, o])),
table = attendees.map(({ name, ticket_code }) => [name, ticketsByCode [ticket_code].name]);
console.log(table);

试试这个：

let a = [
{name: 'Jack', ticket_code: 'iGh4rT'},
{name: 'Lisa', ticket_code: 'it1ErB'}
];
let b = [
{code: 'iGh4rT', name: 'General Admission'},
{code: 'it1ErB', name: 'VIP'}
];
let c = b.map(item => {
return {
tiketName: item.name,
...a.find(itemA => itemA.ticket_code == item.code)
}
});
console.log(c);