如何控制nodejs打开的浏览器

Question

我想知道如何控制已经打开的浏览器？我已经阅读了API文档，但我找不到方法

---

类似java

ChromeOptions options = new ChromeOptions();
options.setExperimentalOption("debuggerAddress", "127.0.0.1:9222");
WebDriver driver = new ChromeDriver(options);

或python

chrome_options = Options()
chrome_options.add_experimental_option("debuggerAddress", "127.0.0.1:9222")
driver = webdriver.Chrome(chrome_driver, chrome_options=chrome_options)

但是如何通过nodejs(javascript(做到这一点呢
我很困惑

Answer 1

取自https://medium.com/dailyjs/how-to-setup-selenium-on-node-environment-ee33023da72d

下面的脚本将打开chrome浏览器，输入一个术语，提交表单，并返回页面标题。如果测试成功，那么应该打印出通过的测试

const webdriver = require('selenium-webdriver'),
By = webdriver.By,
until = webdriver.until;
const driver = new webdriver.Builder()
.forBrowser('chrome')
.build();
driver.get('http://www.google.com').then(function(){
driver.findElement(webdriver.By.name('q')).sendKeys('webdrivern').then(function(){
driver.getTitle().then(function(title) {
console.log(title)
if(title === 'webdriver - Google Search') {
console.log('Test passed');
} else {
console.log('Test failed');
}
driver.quit();
});
});
});

Answer 2

以下步骤将帮助您：

require('chromedriver');
var webdriver = require('selenium-webdriver');
var chrome = require("selenium-webdriver/chrome");
var chrome = require("selenium-webdriver/chrome");
var options = new chrome.Options();
options.options_["debuggerAddress"] = "127.0.0.1:9222";
var driver = new webdriver.Builder()
.forBrowser('chrome')
.setChromeOptions(options)
.build();
driver.get("https://www.google.com")