使用ModelViewSet在URL中传递自定义参数

Question

使用ModelViewSet传递param的最佳方式是什么？例如，实现这样的目标：

http://127.0.0.1:8000/api/v1/financing-settings/template/?param=block

以下是我使用的方法，但发现我已经在正文部分设置了参数，但这不是我想要的：

class TemplateView(ModelViewSet):
"""ViewSet for Saving Block/ Step template."""

def list(self, request, *args, **kwargs):
"""Get list of Block/Steps with is_process_template is equal to True."""
param = request.data['param']
if param == "block":
_block = Block.objects.filter(is_process_template=True).values()
return JsonResponse({"data": list(_block)}, safe=False, status=200)
elif param == "step":
_step = Step.objects.filter(is_process_template=True).values()
return JsonResponse({"data": list(_step)}, safe=False, status=200)
return Response(status=status.HTTP_204_NO_CONTENT)

Answer 1

param = request.GET.get('param')

或请求后

param = request.POST.get('param')

Answer 2

param=request.query_params.get('param'(