我想创建多个DAOS文件以更好地组织项目,即使我只有一个数据库。当我尝试按照这些行做一些事情时,它工作了:
@Database(version = 1, entities = [ContaBancaria::class])
abstract class CArchDatabase : RoomDatabase() {
abstract fun contaBancariaDao(): ContaBancariaDao
companion object {
fun createDatabase(context: Context): RoomDatabase {
return Room.databaseBuilder(context, CArchDatabase::class.java, "CArchDatabase.db")
.fallbackToDestructiveMigration()
.build()
}
}
}
然而,当我尝试这样做时,它不起作用:
@Database(version = 1, entities = [ContaBancaria::class, entity1, entity2,entity3 ....])
abstract class CArchDatabase : RoomDatabase() {
abstract fun contaBancariaDao(): ContaBancariaDao
abstract fun dao1(): dao1
abstract fun dao2(): dao2
abstract fun dao3(): dao3
abstract fun dao4(): dao4
.
.
.
companion object {
fun createDatabase(context: Context): RoomDatabase {
return Room.databaseBuilder(context, CArchDatabase::class.java, "CArchDatabase.db")
.fallbackToDestructiveMigration()
.build().dao1().dao2().dao3()....
}
}
}
我使用koin单例创建我的数据库
val cacheDataModule = module {
single { CArchDatabase.createDatabase(androidContext()) }
factory<ContaBancariaCacheDataSource> {
ContaBancariaCacheDataSourceImpl(
contaBancariaDao = get()
)
}
}
每个数据库DAO必须有一个定义操作的@Dao
类(查看文档:https://developer.android.com/training/data-storage/room#dao)
从你的代码,我假设你已经有一个ContaBancariaDao
类。如果您想创建更多的DAO,则需要创建与此类似的新类。
那么你只需要在你的CArchDatabase
中添加一个新的fun
。
如果您还想添加新的实体,请记住将它们添加到@Database
注释的entities
数组中。
@Database(entities = arrayOf(ContaBancaria::class, Other::class), version = 1)
abstract class CArchDatabase : RoomDatabase() {
abstract fun contaBancariaDao(): ContaBancariaDao
abstract fun otherDao(): OtherDao
companion object {
fun createDatabase(context: Context): RoomDatabase {
return Room.databaseBuilder(context, CArchDatabase::class.java, "CArchDatabase.db")
.fallbackToDestructiveMigration()
.build()
}
}
}