身份测试游戏的生活

Question

我正在用python编写conway的游戏代码。我的代码是这样的:

def update_board(board: list[list[int]]) -> list[list[int]]:
rows = len(board)
cols = len(board[0])
count = 0
copy_board = deepcopy(board)
indx = [-1, -1, -1, 0, 0, 1, 1, 1]
indy = [-1, 0, 1, -1, 1, -1, 0, 1]
for i in range(rows):
for j in range(cols):
for k, value in enumerate(indx):
if check(i + value, j + indy[k], rows,
cols) and copy_board[i + indx[k]][j + indy[k]]:
count += 1
# Apply the rule to each cell
if count < 2 or count > 3:
board[i][j] = 0
elif count == 3:
board[i][j] = 1
# Reset the count for the next cell
count = 0
return board

需要通过身份测试:

def test_is_not_identity() -> None:
"""Test board update is not done in place."""
board = [[0 for _ in range(4)] for _ in range(4)]
assert board is not update_board(board)

和静态测试(我不知道它是做什么的):

def test_stills(name: str, proto: str) -> None:
"""Test still lifes."""
board = parse_board(proto)
assert board == update_board(deepcopy(board)), name

但它没有通过，虽然我更新了董事会的地方，所以我不明白。

Answer 1

您应该返回copy_board而不是board。也修改copy_booard而不是board本身

def update_board(board: list[list[int]]) -> list[list[int]]:
rows = len(board)
cols = len(board[0])
count = 0
copy_board = deepcopy(board)
indx = [-1, -1, -1, 0, 0, 1, 1, 1]
indy = [-1, 0, 1, -1, 1, -1, 0, 1]
for i in range(rows):
for j in range(cols):
for k, value in enumerate(indx):
if check(i + value, j + indy[k], rows,
cols) and board[i + indx[k]][j + indy[k]]:
count += 1
# Apply the rule to each cell
if count < 2 or count > 3:
copy_board[i][j] = 0
elif count == 3:
copy_board[i][j] = 1
# Reset the count for the next cell
count = 0
return copy_board