在alpha数字字符串上先按文本然后按数字排序

Question

我有一个像这样的数组

["1","0K","11",1,"KE","PQ",5,"5"]

我想让它先按文本然后按数字排序，就像下面的

["KE","PQ","0K","1",1,5,"5","11"]

我使用local compare，但它似乎没有工作。

function desc(a,b){
//below is the code that needs improvement
return b.toString().localeCompare(a, undefined, {
numeric: true,
sensitivity: "base",
});
}
function sort(order) {
return order === "desc"
? (a, b) => desc(a, b)
: (a, b) => -desc(a, b);
}
function stableSort(array, cmp){
const stabilizedThis = array.map((el, index) => [el, index]);
stabilizedThis.sort((a, b) => {
const order = cmp(a[0], b[0]);
if (order !== 0) return order;
return (a[1]) - (b[1]);
});
return stabilizedThis.map((el) => el[0]);
}
var arr = ["1","0K","11",1,"KE","PQ",5,"5"];
console.log(stableSort(arr, sort("asc")))

Answer 1

您可以编写filter方法来获取strings containing numbers，删除条目，从rest中单独获得numbers和strings，然后按您喜欢的方式排序。

const data = ["1","0K","11",1,"KE","PQ",5,"5"];
const stringsWithNumbers = data.filter(x => /d+[a-zA-Z]/.test(x));
const rest = data.filter(x => !stringsWithNumbers.includes(x));
const numbers = rest.filter((x) => parseInt(x, 10));
const words = rest.filter((x) => !parseInt(x, 10));
const result = [
...words.sort((a, b) => a.localeCompare(b)), 
...stringsWithNumbers.concat(numbers).sort((a, b) => parseInt(a) - parseInt(b)),
];
console.log(result);

Answer 2

const sort = (arr = []) => {
const nonAlpha = /[^a-zA-Z]/g, nonNum = /[^0-9]/g;
return arr.sort((a, b) => {
const aStr = String(a), bStr = String(b);
const aAlpha = aStr.replace(nonAlpha, ""), bAlpha = bStr.replace(nonAlpha, "");
const alphaCompare = bAlpha.localeCompare(aAlpha);
if(alphaCompare) return alphaCompare;
const aNum = +aStr.replace(nonNum, ""), bNum = +bStr.replace(nonNum, "");
return aNum - bNum;
});
}
console.log( sort(["1","0K","11",1,"KE","PQ",5,"5"]) );

Answer 3

var arr = ["1","OK","11",1,"KE","PQ",5,"5"]
var wordArr = []
var numArr = []
arr.forEach((el) => {
if(Number(el)){
numArr.push(el)
} else {
wordArr.push(el)
}
});
wordArr.sort()
numArr.sort((a, b) => a - b)
arr = wordArr.concat(numArr)
console.log(arr)