从文件名获取字符串值的正则表达式模式

Question

我坚持用下划线分隔符获取值。我使用preg_match(PHP)，但没有得到正确的正则表达式模式。这是文件名的示例模式。

xxxx_get-thisValue_more details_20200728173715594600.zipget-thisValue_more details_20200728173715594600.zipgetThisValue_20200728173715594600.zip

我想要的是在文件名模式上获得get- thisvalue或getThisValue字符串，提前感谢顺便说一下，这是我的代码

<?php 
$filename = 'xxxx_get-thisValue_more details_20200728173715594600.zip';
preg_match('/(.*_)?(.*)_[0-9]+.zip/', $filename, $matches);
echo $prefix = $matches[2];

?比;

Answer 1

例如，您可以使用一个捕获组:

([^_s]+)(?:_[^n_-]+)?_d+.zip$

• ([^_s]+)捕获组1，匹配除_(或空格)以外的任何字符
• (?:_[^n_-]+)?可选地匹配_，然后匹配_或-以外的任何字符
• _d+.zip匹配_1 +数字和.zip
• $字符串结束

Regex演示

例子

$re = '/([^_s]+)(?:_[^n_-]+)?_d+.zip$/m';
$str = 'xxxx_get-thisValue_more details_20200728173715594600.zip
get-thisValue_more details_20200728173715594600.zip
getThisValue_20200728173715594600.zip
xxxx_get-thisValue_more details_20200728173715594600.zip
xxxx_getthisValue_more details_20200728173715594600.zip
1111_get-thisValue_more details_20200728173715594600.zip
1111_getthisValue_more details_20200728173715594600.zip
get-thisValue_more details_20200728173715594600.zip
getthisValue_more details_20200728173715594600.zip
get-thisValue_20200728173715594600.zip
getthisValue_20200728173715594600.zip';
preg_match_all($re, $str, $matches);
print_r($matches[1]);

输出

Array
(
[0] => get-thisValue
[1] => get-thisValue
[2] => getThisValue
[3] => get-thisValue
[4] => getthisValue
[5] => get-thisValue
[6] => getthisValue
[7] => get-thisValue
[8] => getthisValue
[9] => get-thisValue
[10] => getthisValue
)

查看PHP演示。