Webtau -可以在JUnit测试中使用TableData来验证REST响应JSON是否包含所有给定的条目?<

Question

Webtau提供了一些非常有表现力的快捷方式，比如TableData。我目前正在使用JUnit。例如，用于测试来自REST端点的预期数据，例如:

[
{ "uuid": "1-2-3-4", "directionShort": "N", "direction": "North" },
{ "uuid": "1-2-3-5", "directionShort": "S", "direction": "South" },
{ "uuid": "1-2-3-6", "directionShort": "E", "direction": "East" },
{ "uuid": "1-2-3-7", "directionShort": "W", "direction": "West" }
]

我可以这样写(是的，当然这个例子有点夸张):

import static org.assertj.core.api.Assertions.assertThat;
import static org.testingisdocumenting.webtau.WebTauDsl.http;
import static org.testingisdocumenting.webtau.Matchers.equal;
import static org.testingisdocumenting.webtau.WebTauCore.table;
import static org.testingisdocumenting.webtau.WebTauCore.____________;
http.get(URL_CARDINAL_POINTS,
(header, body) -> {
header.get("statusCode").shouldBe(equal(200));
assertThat(body.isList()).isTrue();
assertThat(body.numberOfElements()).isEqualTo(4);
body.should(equal(table(
"*directionShort", "direction",
____________,
"N", "North",
"S", "South",
"E", "East",
"W", "West"
)));
}
);

对于小的值集是可行的。对于较大的数据集，我想用containAll进行测试，例如:

[
{ "uuid": "...", "name": "Stockholm", "country": "Sweden", "population": 10.42 },
{ "uuid": "...", "name": "Kiew", "country": "Ukraine", "population": 10.42 },
...
]

import static org.testingisdocumenting.webtau.Matchers.containAll;
http.get(URL_CAPITAL_CITIES,
(header, body) -> {
header.get("statusCode").shouldBe(equal(200));
assertThat(body.isList()).isTrue();
assertThat(body.numberOfElements()).isGreaterThan(10);
body.should(containAll(table(
"*name", "country", "population",
________________________________,
"Paris", "France", 2.161,
"Berlin", "Germany", 3.645,
"Kiew", "Ukraine", 2.884,
"Oslo", "Norway", 0.634,
"Madrid", "Spain", 3.223
)));
}
);

我试过了:

但这不起作用，它失败了:IllegalArgumentException: column 'name' is not present。

省略键列标记时(name&quot前面的*;列)，错误变为:

body.should(containAll(table("name", "country", [...])
-->
"expecting body to contain all [<the table>]: no matches found for [<the table>]"

当使用contain()代替containAll时:

body.should(contain(table("name", "country", [...])
-->
"AssertionError: no match found"

丑陋的解决方案:

检查"manually"匹配:

Object dataNode;
dataNode = body.find(it -> "Paris".equals(it.get("name").get()));
assertThat(dataNode).isNotNull();
dataNode = body.find(it -> "Kiew".equals(it.get("name").get()));
assertThat(dataNode).isNotNull();
dataNode = body.find(it -> "Oslo".equals(it.get("name").get()));
assertThat(dataNode).isNotNull();
...

在试图比较除"键"以外的更多属性时，这是非常繁琐的。

仍然……丑陋的解决方案:

仍然与table的表达性相距甚远，因为键使数据混乱:

import static org.testingisdocumenting.webtau.utils.CollectionUtils.map;
body.should(containAll(
map("name", "Paris", "country", "France", "population": 2.161),
map("name", "Berlin", "country", "Germany", "population": 3.645),
map("name", "Kiew", "country", "Ukraine", "population": 2.884),
map("name", "Oslo", "country", "Norway", "population": 0.634),
map("name", "Madrid", "country", "Spain", "population": 3.223)
));

问题:

是否有办法使用数据表table而不是map序列?

body.should(containAll(table(
"*name", "country", "population",
________________________________,
"Paris", "France", 2.161,
"Berlin", "Germany", 3.645,
"Kiew", "Ukraine", 2.884,
"Oslo", "Norway", 0.634,
"Madrid", "Spain", 3.223
)));

Answer 1

我认为这是一个很好的建议!我将不得不在WebTau中添加一条新规则以使其发挥作用。我理解你的意图，这是有道理的。

语法为

body.should(contain(table))

现在发布:https://testingisdocumenting.org/webtau/HTTP/matchers#contain-table

也非常高兴你使用table!请随意加入不和谐服务器，我很想了解更多关于你的经验，想法和反馈。