如何使用导航器检测勇敢

Question

我正在尝试使用导航器检测勇敢。我参考了这篇文章，https://stackoverflow.com/a/60954062/14443512

我尝试了这个条件，(navigator.brave && await navigator.brave.isBrave() || false)

但是我得到错误，Property 'brave' does not exist on type 'Navigator'.

我在这里缺少任何配置吗?

我的代码块

export const errorMessage = (networkError: netError): string | undefined => {
const {statusCode, message} = networkError;
if (statusCode === undefined) {
return message;
}
if (statusCode < 400) {
return undefined;
}
switch (statusCode) {
case 401:
return 'authn error';
case 403:
if(navigator.brave && await navigator.brave.isBrave() || false)
return 'browser not supported';
else 
return 'authz error';
case 500:
if (message.includes("invalid value")) {
return invalidString;
}
break;
}
if (statusCode < 500) {
return 'error';
}
return 'serverError';
};

Answer 1

我认为声明应该是这样的:

export {}; // there must be at least one export in this file
declare global {
interface Navigator {
brave: {
isBrave(): boolean;
};
}
interface Global {
document: Document;
window: Window;
navigator: Navigator,
} 
}