无限循环，同时制作一个简单的逻辑游戏"Bagels"

Question

我正在使用小Python项目的大书来提高我的Python技能，并且在第一个项目上，这是一个简单的逻辑游戏，在第一次尝试中，代码一路走，但是如果你错了，你就不会正常运行。

这是游戏的代码和描述，有机会的while循环应该在整个游戏中运行，直到你的机会用完，第二个while循环应该在用户输入长度小于或大于3的数字

时运行

import re
import random
#In Bagels, a deductive logic game, you
#must guess a secret three-digit number
#based on clues. The game offers one of
#the following hints in response to your guess:
#“Pico” when your guess has a correct digit in the
#wrong place, “Fermi” when your guess has a correct
#digit in the correct place, and “Bagels” if your guess
#has no correct digits. You have 10 tries to guess the
#secret number.

choice_of_nums=['123','345','674','887','356','487','916']
random_three_num=random.choices(choice_of_nums)
count_bagel=0
count_fermi=0
Chances=10
while Chances!=0:
guess = input(f'Guess the three digit number! You have {Chances} to guess! ')
while len(guess)!=3:
guess=input('You must choose a three digit number! Try again! ')
for i in range(0,len(random_three_num)):
if guess==random_three_num:
print('YOU WIN! Well done')
break
elif guess[i] not in random_three_num:
count_bagel+=1
if count_bagel==len(random_three_num):
print('Bagels')
Chances=Chances-1
elif guess[i]==random_three_num[i]:
count_fermi+=1
Chances=Chances-1
print('Fermi')
elif guess in random_three_num:
print('Pico')

Answer 1

import random
choice_of_nums = ['123', '345', '674', '887', '356', '487', '916']
random_three_num = random.choice(choice_of_nums)
count_bagel = 0
count_fermi = 0
chances = 10
while chances > 0:
guess = input(f'Guess the three digit number! You have {chances} to guess! ')
while len(guess) != 3:
guess = input('You must choose a three digit number! Try again! ')
while not guess.isdigit():
guess = input('You must choose integer values! ')
number_is_present = any(number in guess for number in random_three_num)
if guess == random_three_num:
print('YOU WIN! Well done')
chances = 1  # combined w/ the last line, chances will become = 0
elif not number_is_present:
print('Bagel')
else:
index_is_right = False
for i in range(len(guess)):
if guess[i] == random_three_num[i]:
index_is_right = True
if index_is_right:
print('Fermi')
else:
print('Pico')
chances -= 1

• (06/28/22)添加chances = 1，如果猜对了，那么退出while循环

• random.choices返回一个列表

• 你不需要re模块

• 按照PEP8

  建议使用蛇形案例

Answer 2

print('YOU WIN! Well done')之后的break退出for循环而不是while循环． 把Chances = 0放到break前面:

if guess==random_three_num:
print('YOU WIN! Well done')
Chances = 0
break

Answer 3

1. 永远不要用x != 0这样的条件检查while循环。始终使用<=或>=。原因是，如果数字0被跳过，最终到达-1，那么循环仍然会退出。

2. 你不能在for循环之前检查if guess==random_three_num:吗?然后break语句实际上会中断while循环。现在它只是中断了for循环。这是可能导致无限循环的一个原因。

3. 你的倒数第二行elif guess in random_three_num:应该是elif guess[1] in random_three_num:。

4. Chances=Chances-1也可能在for循环之外，因为每次猜测的机会数量应该只减少一次。目前，在for循环期间，机会的数量最多减少3倍(每次你击中'Fermi')。这可能导致"1.">

   中描述的问题。