如何在nginx中拦截所有传出的响应并修改它们?

Question

我有一个nginx服务器，通过php提供论坛。我想添加一个上游到nginx，拦截php应用程序生成的所有响应并修改响应。

是否有可能通过修改nginx配置文件来实现这一点?

下面是我现有的配置:

server {
listen 443 ssl;
server_name example.net www.example.net;
index index.php index.html;
root /var/www/html;
location / {
try_files $uri $uri/ /index.php?$uri&$args;
}
location ~ .php$ {
fastcgi_split_path_info ^(.+.php)(/.+)$;
fastcgi_pass xf2-php-fpm:9000;
fastcgi_index index.php;
include fastcgi_params;
fastcgi_param SCRIPT_FILENAME     $document_root$fastcgi_script_name;
fastcgi_param PATH_INFO $fastcgi_path_info;
}
}

如何修改此配置以将php生成的所有响应传递给上游?

Answer 1

你可以在当前的上游块之外添加一个新的上游块，定义你想要使用的服务器/服务器作为上游

upstream upStream{
server upStream_server:4000;
}

然后修改处理PHP请求的location块，将请求代理到上游服务器

location ~ .php$ {
proxy_pass http://upStream; #URL to which the request should be proxied
proxy_set_header Host $host; #Hostname of the server to which the request is being sent to
proxy_set_header X-Real-IP $remote_addr; #IP address of the client that made the request
proxy_set_header X-Forwarded-For $proxy_add_x_forwarded_for; #IP address of the client that made the request and any other IP addresses that the request was forwarded through
//
}

这应该将所有请求传递给上游服务器，并将响应发送回客户端。如果你需要更多的帮助，告诉我