查询以获得所需的输出

Question

我有一个表，其中有以下示例输出:

ID_Emp| Name    |   Date          
11    |Jonh     |14/05/2014 8:16
11    |Jonh     |14/05/2014 13:35
11    |Jonh     |14/05/2014 17:23
11    |Jonh     |14/05/2014 21:09
12    |Elizabe  |14/05/2014 14:06
12    |Elizabe  |14/05/2014 20:39
12    |Elizabe  |14/05/2014 21:39
12    |Elizabe  |14/05/2014 22:39
13    |Jimmy    |14/05/2014 8:00
13    |Jimmy    |14/05/2014 17:12
13    |Jimmy    |14/05/2014 18:12

我想要构建一个查询来实现以下结果:

ID_Emp|Name  |Date          |TimeIn1 |TimeOut1||TimeIn2|TimeOut2|Hours
11  |Jonh    |14/05/2014    |8:16   |13:35     |17:23  |21:09  |5:19
12  |Elizabe |14/05/2014    |14:06  |20:39     |21:39  |22:39  |8:33
13  |Jimmy   |14/05/2014    |8:00   |17:12     |18:12  |  -    |9:12

查询:

SELECT cio.emp_reader_id, cio.dt AS CheckIn, 
cio.next_dt as CheckOut
FROM (SELECT cio.*,
ROW_NUMBER() OVER (PARTITION BY cio.emp_reader_id, CONVERT(date, cio.dt) ORDER BY cio.dt) as seqnum,
LEAD(cio.dt) OVER (PARTITION BY cio.emp_reader_id, CONVERT(date, cio.dt) ORDER BY cio.dt) as next_dt
FROM trnevents cio 
) cio 
WHERE seqnum % 2 = 1

Answer 1

这里使用多个CTE进行计算。此查询适用于每个emp_id的每个日期。使用格式功能转换日期和小时:分钟。

-- SQL Server
WITH cte AS (SELECT ID_Emp
, Name
, CAST(tdate AS date) actual_date
, tdate
, ROW_NUMBER() OVER (PARTITION BY ID_Emp, CAST(tdate AS date) ORDER BY tdate) row_num
FROM test
), cte2 AS (
SELECT ID_Emp
, MAX(Name) Name
, actual_date
, MAX(CASE WHEN row_num = 1 THEN tdate END) TimeIn1
, MAX(CASE WHEN row_num = 2 THEN tdate END) TimeOut1
, MAX(CASE WHEN row_num = 3 THEN tdate END) TimeIn2
, MAX(CASE WHEN row_num = 4 THEN tdate END) TimeOut2
FROM cte
GROUP BY ID_Emp, actual_date
)
SELECT ID_Emp, Name
, FORMAT(actual_date, 'dd/MM/yyyy') date
, FORMAT(TimeIn1, 'HH:mm') TimeIn1
, FORMAT(TimeOut1, 'HH:mm') TimeOut1
, FORMAT(TimeIn2, 'HH:mm') TimeIn2
, FORMAT(TimeOut2, 'HH:mm') TimeOut2
, CAST((DATEDIFF(second, TimeIn1, TimeOut1)/3600) AS VARCHAR(2)) + ':' +
CAST(((DATEDIFF(second, TimeIn1, TimeOut1)%3600)/60) AS VARCHAR(2)) Hours
FROM cte2
ORDER BY ID_Emp

使用子查询

SELECT t.ID_Emp, t.Name
, FORMAT(t.actual_date, 'dd/MM/yyyy') date
, FORMAT(t.TimeIn1, 'HH:mm') TimeIn1
, FORMAT(t.TimeOut1, 'HH:mm') TimeOut1
, FORMAT(t.TimeIn2, 'HH:mm') TimeIn2
, FORMAT(t.TimeOut2, 'HH:mm') TimeOut2
, CAST((DATEDIFF(second, t.TimeIn1, t.TimeOut1)/3600) AS VARCHAR(2)) + ':' +
CAST(((DATEDIFF(second, t.TimeIn1, t.TimeOut1)%3600)/60) AS VARCHAR(2)) Hours
FROM (SELECT p.ID_Emp
, MAX(p.Name) Name
, p.actual_date
, MAX(CASE WHEN p.row_num = 1 THEN p.tdate END) TimeIn1
, MAX(CASE WHEN p.row_num = 2 THEN p.tdate END) TimeOut1
, MAX(CASE WHEN p.row_num = 3 THEN p.tdate END) TimeIn2
, MAX(CASE WHEN p.row_num = 4 THEN p.tdate END) TimeOut2
FROM (SELECT ID_Emp
, Name
, CAST(tdate AS date) actual_date
, tdate
, ROW_NUMBER() OVER (PARTITION BY ID_Emp, CAST(tdate AS date) ORDER BY tdate) row_num
FROM test     
) p
GROUP BY ID_Emp, actual_date) t
ORDER BY t.ID_Emp

请从此网址https://dbfiddle.uk/?rdbms=sqlserver_2017&fiddle=54f542847167481298b168d6b0a8d6b9查看

Answer 2

enter code here

选择Id、名称、日期、TimeIn1, TimeOut1 TimeIn2select (select Id,Name,Date,time, TimeIn1,lead(a.time) over(Id,a.Name,a. Name))日期(按时间排序)作为TimeOut1* * * * * * * * * * * * * * * * *日期(按时间排序)为TimeIn2，ROW_NUMBER()Over(Partition by a.Id,a.Name,a.)日期(按时间排序)为rn从(select Id,Name，将(date as date)转换为日期，将(date as time)转换为时间from Stack)a)b where rn=1