python3中的urllib异常处理



我正在尝试捕获urllib错误:

Traceback (most recent call last):
File "/usr/lib64/python3.7/urllib/request.py", line 1317, in do_open
encode_chunked=req.has_header('Transfer-encoding'))
File "/usr/lib64/python3.7/http/client.py", line 1229, in request
self._send_request(method, url, body, headers, encode_chunked)
File "/usr/lib64/python3.7/http/client.py", line 1275, in _send_request
self.endheaders(body, encode_chunked=encode_chunked)
File "/usr/lib64/python3.7/http/client.py", line 1224, in endheaders
self._send_output(message_body, encode_chunked=encode_chunked)
File "/usr/lib64/python3.7/http/client.py", line 1016, in _send_output
self.send(msg)
File "/usr/lib64/python3.7/http/client.py", line 956, in send
self.connect()
File "/usr/lib64/python3.7/http/client.py", line 928, in connect
(self.host,self.port), self.timeout, self.source_address)
File "/usr/lib64/python3.7/socket.py", line 707, in create_connection
for res in getaddrinfo(host, port, 0, SOCK_STREAM):
File "/usr/lib64/python3.7/socket.py", line 748, in getaddrinfo
for res in _socket.getaddrinfo(host, port, family, type, proto, flags):
socket.gaierror: [Errno -2] Name or service not known
During handling of the above exception, another exception occurred:
Traceback (most recent call last):
File "main.py", line 190, in on_search_click
res = ast.literal_eval(urlopen(url).read().decode())
File "/usr/lib64/python3.7/urllib/request.py", line 222, in urlopen
return opener.open(url, data, timeout)
File "/usr/lib64/python3.7/urllib/request.py", line 525, in open
response = self._open(req, data)
File "/usr/lib64/python3.7/urllib/request.py", line 543, in _open
'_open', req)
File "/usr/lib64/python3.7/urllib/request.py", line 503, in _call_chain
result = func(*args)
File "/usr/lib64/python3.7/urllib/request.py", line 1345, in http_open
return self.do_open(http.client.HTTPConnection, req)
File "/usr/lib64/python3.7/urllib/request.py", line 1319, in do_open
raise URLError(err)
urllib.error.URLError: <urlopen error [Errno -2] Name or service not known>

我试过:

except URLError:
...

以及

except urllib.error.URLError:

但已知的是他们给出了错误,只是打印了上面的回溯。我应该如何发现错误?

试试这个,它对我有用:

import urllib.error
...
try:
post = urllib.request.urlopen(request)
print(post.__dict__)
except urllib.error.HTTPError as e:
print(e.__dict__)
except urllib.error.URLError as e:
print(e.__dict__)

我希望它对你有用。

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