已解决
原来我在修复JSON时把它搞砸了。谢谢你的帮助。向我展示了一些使用json的新方法：(
我搜索了很多其他问题，尝试了答案，有些做了一些事情，有些只是抛出了一个错误。如果成功的话，它将整个元数据列表(包括我想要的json数据(记录到控制台：
{…}
abort: function abort(e)
always: function always()
catch: function catch(e)
done: function add()
fail: function add()
getAllResponseHeaders: function getAllResponseHeaders()
getResponseHeader: function getResponseHeader(e)
overrideMimeType: function overrideMimeType(e)
pipe: function pipe()
progress: function add()
promise: function promise(e)
readyState: 4
responseText: "<JSON content>"
setRequestHeader: function setRequestHeader(e, t)
state: function state()
status: 200
statusCode: function statusCode(e)
statusText: "OK"
then: function then(t, n, r)
<prototype>: Object { … }
所以，我的问题是：如何从中获取json内容？
使用的代码：
function start() {
var j = $.ajax({
url: 'users.json',
type: "GET",
dataType: "json",
success: function (data) {
console.log(data);
}
});
}
Json：
"UsersByID":[ {
"id": 1
"Name": ["K", "L", "Smiths"],
"Birthday": ["03", "10", "1987"],
"Username": "user1",
"Password": "verysafepassword",
"Hollidays": [{
"HollidayId": 1
"HollidayType": 2,
"AmountOfPeople": 5,
"Date": ["18", "08", "2020"]
}{
"HollidayId": 2
"HollidayType": 3,
"AmountOfPeople": 2,
"Date": ["24", "10", "2020"]
}
}]
}]
}
}
您通常所做的(在纯javascript中(是过滤传递的JSON。由于我不知道你想要过滤什么，一些伪代码是如何工作的：
function start() {
var j = $.ajax({
url: 'users.json',
type: "GET",
dataType: "json",
success: function (response) { //data is a keyword so better use response
console.log(response);
response.data.forEach(function(field) { // we iterate through each field in the JSON
if (field.typeField == "UsersByID") { // Given the JSON part looks like {"UsersByID":{"myBigData": "secrets","yourBigData": "noSecrets"}}
console.info("My content found");
// Do whatever you have to do with the content
}
}); // for each END
}
});
}
EDITT要处理JSON，有不同的可能性。如果你知道混合了什么，你可以像我上面所做的那样进行过滤，然后对结果进行处理
另一种方法是，如果您不必提取，但整个响应是所需的JSON，您可以按如下方式(当然也可以组合(
function start() {
var j = $.ajax({
url: 'users.json',
type: "GET",
dataType: "json",
success: function (response) { //data is a keyword so better use response
console.log(response);
var myObj = JSON.parse(response);
// Do whatever you have to do with myObj e.g.
var u_username = myObj.Username; // you retrieve from the object with the field names
// when nested you get a new object and then you retrieve
var objHollidays = myObj.Hollidays;
var u_HollidayId = objHollidays.HollidayId;
// OR you iterate over all objHollidays
objHollidays.HollidayId.forEach(function(field) { // we iterate through each
//Do whatever you need
});
}
});
}
JSON中不允许分析日期
日期对象
如果需要包含日期，请将其写成字符串
您可以稍后将其转换回日期对象：
var text = '{ "name":"John", "birth":"1986-12-14", "city":"New York"}';
var obj = JSON.parse(text);
obj.birth = new Date(obj.birth);