我的问题类似于此:R dplyr rowwise mean或min和其他方法?想知道是否有任何dplyr函数(或函数的组合,如pivot_
等(,可以在通常的dplyr一行中提供所需的输出?
library(tidyverse); set.seed(1);
#Sample Data:
sampleData <- data.frame(O = seq(1, 9, by = .1), A = rnorm(81), U = sample(1:81,
81), I = rlnorm(81), R = sample(c(1, 81), 81, replace = T)); #sampleData;
#NormalOuput:
NormalOuput <- sampleData %>% summarise_all(list(min = min, max = max));
NormalOuput;
#> O_min A_min U_min I_min R_min O_max A_max U_max I_max R_max
#> 1 1 -2.2147 1 0.1970368 1 9 2.401618 81 14.27712 81
#Expected output:
ExpectedOuput <- data.frame(stats = c('min', 'max'), O = c(1, 9), A = c(-2.2147,
2.401618), U = c(1, 81), I = c(0.1970368, 14.27712), R = c(1, 81));
ExpectedOuput;
#> stats O A U I R
#> 1 min 1 -2.214700 1 0.1970368 1
#> 2 max 9 2.401618 81 14.2771200 81
由reprex包于2020-08-26创建(v0.3.0(
注意:
在实际场景中,列的数量可能很大,因此无法直接调用名称。
编辑
充其量,我得到的是:
sampleData %>% summarise(across(everything(), list(min = min, max = max))) %>%
t() %>% data.frame(Value = .) %>% tibble::rownames_to_column('Variables')
Variables Value
1 O_min 1.0000000
2 O_max 9.0000000
3 A_min -2.2146999
4 A_max 2.4016178
5 U_min 1.0000000
6 U_max 81.0000000
7 I_min 0.1970368
8 I_max 14.2771167
9 R_min 1.0000000
10 R_max 81.0000000
我建议混合使用tidyverse
函数,如下所示。你必须重塑你的数据,然后用你想要的汇总函数进行聚合,然后作为策略,你可以再次重新格式化并获得预期的输出:
library(tidyverse)
sampleData %>% pivot_longer(cols = names(sampleData)) %>%
group_by(name) %>% summarise(Min=min(value,na.rm=T),
Max=max(value,na.rm=T)) %>%
rename(var=name) %>%
pivot_longer(cols = -var) %>%
pivot_wider(names_from = var,values_from=value)
输出:
# A tibble: 2 x 6
name A I O R U
<chr> <dbl> <dbl> <dbl> <dbl> <dbl>
1 Min -2.21 0.197 1 1 1
2 Max 2.40 14.3 9 81 81
您可以使用新的ishacross()
来消除Duck的一个支点:
sampleData %>%
summarise(across(everything(),
list(min = min, max = max))) %>%
pivot_longer(
cols = everything(),
names_to = c("var", "stat"),
names_sep = "_"
) %>%
pivot_wider(id_cols = "stat",
names_from = "var")
# # A tibble: 2 x 6
# stat O A U I R
# <chr> <dbl> <dbl> <dbl> <dbl> <dbl>
# 1 min 1 -2.21 1 0.197 1
# 2 max 9 2.40 81 14.3 81
但最好的可能是马库斯在评论中的建议,我在这里进行了调整:
map_dfr(sampleData, function(x) c(min(x), max(x))) %>%
mutate(stat = c("min", "max"))
# # A tibble: 2 x 6
# O A U I R stat
# <dbl> <dbl> <int> <dbl> <dbl> <chr>
# 1 1 -2.21 1 0.197 1 min
# 2 9 2.40 81 14.3 81 max
在玩pivot_longer
时,我发现这种两步一行的方法也有效(基于@Gregor Thomas的答案,这里只有一个pivot_
,而不是两个或多个(:
sampleData %>%
summarise(across(everything(), list(min, max))) %>%
pivot_longer(everything(), names_to = c(".value", "stats"),
names_sep = "_")
# A tibble: 2 x 6
stats O A U I R
<chr> <dbl> <dbl> <int> <dbl> <dbl>
1 1 1 -2.21 1 0.197 1
2 2 9 2.40 81 14.3 81
更多信息:https://tidyr.tidyverse.org/reference/pivot_longer.html#examples