如何在列表中获取游戏对象的组件

Question

我有这个脚本将我选择的游戏对象添加到列表中(在运行时)。

public Transform ParentOfList;
public List<GameObject> Objects3d = new List<GameObject>();
public GameObject ActualSelected;
public void add3DtoList()
{
foreach (Transform child in ParentOfList) // iterate through all first level children
{
if (child.gameObject.activeSelf)
{
Debug.Log($"The child {child.name} is active!");
ActualSelected = child.gameObject;
if (Objects3d.Contains(ActualSelected))
{
Debug.Log("Already exist in list");
}
else
{
Objects3d.Add(ActualSelected); //add the actual gameobject selected in runtime to list
}
}
}
}

PD：父游戏对象同时只有一个子游戏对象处于活动状态。

添加到列表中的每个游戏对象都有一个文本组件，我想从列表中获取这些单独的文本组件并将其放入新的可变文本中。 喜欢：

Text MergeText;
MergeText.text = ListIndex1.text + ListIndex2.text + etc;

我不知道如何实现这一点。一些指导？，谢谢。

已解决，脚本一列表：

public Transform ParentOfList;
public List<GameObject> Objects3d = new List<GameObject>();
public GameObject ActualSelected;
public Text MergeText;
public void add3DtoList()
{
foreach (Transform child in ParentOfList) // iterate through all first level children
{
if (child.gameObject.activeSelf)
{
Debug.Log($"The child {child.name} is active!");
ActualSelected = child.gameObject;
if (Objects3d.Contains(ActualSelected))
{
Debug.Log("Already exist in list");
}
else
{
Objects3d.Add(ActualSelected); //add the actual gameobject selected in runtime to list
}
}
}
MergeText.text = string.Join("n", Objects3d.Select(obj => obj.GetComponent<Text>().text));
}

已解决，脚本为两个列表：

using System;
using System.Collections;
using System.Collections.Generic;
using System.IO;
using System.Linq;
using System.Text;
using UnityEngine;
using UnityEngine.UI;
public class LIST3DOBJECTS : MonoBehaviour
{
public Transform ParentOfListCodigo;
public Transform ParentOfListDesc;
public List<GameObject> Objects3dCodigo = new List<GameObject>();
public List<GameObject> Objects3dDesc = new List<GameObject>();
public GameObject ActualSelectedCode;
public GameObject ActualSelectedDesc;
public Text MergeTextCode;
public Text MergeTextDesc;
public Text MergeLists;
public void add3DtoList()
{       
foreach (Transform child in ParentOfListCodigo) // iterate through all first level children
{
if (child.gameObject.activeSelf)
{
Debug.Log($"The child {child.name} is active!");
ActualSelectedCode = child.gameObject;
if (Objects3dCodigo.Contains(ActualSelectedCode))
{
Debug.Log("Already exist in list");
}
else
{
Objects3dCodigo.Add(ActualSelectedCode); //add the actual gameobject selected in runtime to list
}
}
}
MergeTextCode.text = string.Join("n", Objects3dCodigo.Select(obj => obj.GetComponent<Text>().text)); //first list, show the code (name), of the children gameobject

foreach (Transform child in ParentOfListDesc) // iterate through all first level children
{
if (child.gameObject.activeSelf)
{
Debug.Log($"The child {child.name} is active!");
ActualSelectedDesc = child.gameObject;
if (Objects3dDesc.Contains(ActualSelectedDesc))
{
Debug.Log("Already exist in list");

}
else
{
Objects3dDesc.Add(ActualSelectedDesc); //add the actual gameobject selected in runtime to list

}
}
}
MergeTextDesc.text = string.Join("n", Objects3dDesc.Select(obj => obj.GetComponent<Text>().text)); //second list, show the description of the children gameobject
CleanText();
}
private void CleanText()
{
var list1 = Objects3dCodigo.Select(child => child.GetComponent<Text>().text);
var list2 = Objects3dDesc.Select(child => child.GetComponent<Text>().text);
var zipped = list1.Zip(list2, (l1, l2) => $"{l1}n{l2}");
MergeLists.text = string.Join("n", zipped);
}
}

Answer 1

听起来你想做的是这样的，例如

var stringBuilder = new StringBuilder();
foreach(var child in Objects3d)
{
stringBuilder.Append(child.GetComponent<Text>().text);
}
MergeText.text = stringBuilder.ToString();

或者如果你想使用Linq你也可以做一些类似的事情

MergeText.text = string.Join("", Objects3d.Select(child => child.GetComponent<Text>().text));

除了""，您还可以使用"分隔符" - 分隔符字符串，例如" "或", "或"n"等。

当然，您也可以使用上层方法附加同样的事情。

---

从评论中回答您的后续问题

对于两个列表，您可以采用第一种方法，但按索引迭代，例如

for(var i =0; i< Objects3d.Length; i++)
{  
stringBuilder.Append(Objects3d[i]).Append('n')
.Append(otherList[i]).Append('n'); 
}

或者您可以使用第二种Linq方法并使用.Zip先将两个列表"合并"在一起，我认为例如像这样

var list1 = Objects3d.Select(child => child.GetComponent<Text>().text);
var list2 = OtherList.Select(child => child.GetComponent<Text>().text);
var zipped = list1.Zip(list2, (l1, l2) => $"{l1}n{l2}");
MergeText.text = string.Join("n", zipped);

不过可能会有更优雅的解决方案(目前仅在我的智能手机上)

Answer 2

我不知道你的意思，你可以这样做：var TextsList = Objects3d.Select(object => object.GetComponent<Text>()).ToList()要获取所有对象文本，或者您可以使用 从列表中选择组件的位置 您的值在哪里：

string text = Objects3d.Where(object => object.GetComponent<Text>() = "your_value");
这是基本的 C#