VS代码:如何调试使用Connexion的Flask应用程序

Question

我在启动Flask应用程序时遇到了一个问题。我正试图用Visual Studio代码在调试模式下运行该应用程序，但它无法正常运行。

这是主要模块代码：

import os
import sys
import logging
import argparse
import connexion
import flask
from cwsm import connexion_manager
import connector.config as lc
_CONFIG = None
path = os.path.abspath("./")
lc.initConfig(path + "/connector/config/Legic.ini")
app = connexion.FlaskApp(__name__, specification_dir=path + "/connector/config")
app.add_api("connectore.yaml")
app.run(host="0.0.0.0", port=8080,debug=True)
if __name__ == '__main__':
main()

以下是从launch.json进行调试的配置

{
"name": "Python: Flask",
"type": "python",
"request": "launch",
"module": "flask",
"env": {
"FLASK_APP": "application_hook:FlaskApp('dev')",
"FLASK_ENV": "development",
"FLASK_DEBUG": "0"
},
"args": [
"run",
"--no-debugger"
],
"jinja": true
}

问题是，每次我在调试模式下运行它时，程序都不会执行我的代码，而是显示以下错误：Error: module 'application_hook' has no attribute 'FlaskApp'为什么会发生这种情况？提前感谢

多一点回溯：

(.venv) PS C:UsersfeleDocumentsGit>  cd 'c:UsersfeleDocumentsGit'; & 'c:UsersfeleDocumentsGit.venvScriptspython.exe' 'c:Usersfele.vscodeextensionsms-python.python-2020.9.112786pythonFileslibpythondebugpylauncher' '51724' '--' '-m' 'flask' 'run' '--no-debugger' 
* Serving Flask app "application_hook:FlaskApp('dev')"
* Environment: development
* Debug mode: off
C:UsersfeleDocumentsGit/connector/config/Git.ini
C:UsersfeleDocumentsGit.venvlibsite-packagesconnexionappsflask_app.py:96: Warning: Silently ignoring app.run() because the application is run from the flask command line executable.  Consider putting app.run() behind an if __name__ == "__main__" guard to silence this warning.
self.app.run(self.host, port=self.port, debug=self.debug, **options)
Usage: python -m flask run [OPTIONS]
Error: module 'application_hook' has no attribute 'FlaskApp'
(.venv) PS C:UsersfeleDocumentsGit> 

Answer 1

修复"错误：模块"application_hook"没有属性"FlaskApp">，通过将FLASK_APP设置为启动应用程序的主文件的名称(例如app.py或main.py(来更新launch.json。

此外，由于您使用connexion，launch.json需要更新如下：

• 模块应从flask更改为connexion
• args：
  • 删除--no-debugger
  • 将路径添加到规范文件
  • 添加--port和端口号

launch.json

{
"version": "0.2.0",
"configurations": [
{
"name": "Python: Connexion",
"type": "python",
"request": "launch",
"module": "connexion",
"cwd": "${workspaceFolder}",
"env": {
"FLASK_APP": "app.py",
"FLASK_ENV": "development",
"FLASK_DEBUG": "1"
},
"args": [
"run",
"./connector/config",
"--port",
"8080"
],
"jinja": true
}
]
}

在主模块中，app.run()应放置在__main__防护装置内：

主模块(app.py或Main.py(

path = os.path.abspath("./")
lc.initConfig(path + "/connector/config/Legic.ini")
app = connexion.FlaskApp(__name__, specification_dir=path + "/connector/config")
app.add_api("connectore.yaml")

if __name__ == '__main__':
app.run(host="0.0.0.0", port=8080,debug=True)

Answer 2

我不知道为什么！！！但是，我正在做一个Flask/Conecexion项目。两个月前，我一直在努力在VSCode上调试它。当它在PyCharm上毫无痛苦地发挥作用时，我放弃了。现在，也许是因为一些Linux/VCode？PyCharm更新，相同的源代码不再可以用PyCharm"调试"，而是用最简单的启动器：处理VSCode

"configurations": [
{
"name": "Python: Debug",
"type": "python",
"request": "launch",
"program": "app.py",
"console": "integratedTerminal"
}
]

别问我为什么！这是相同的源代码！是的，我用的是venv。