列表字典和元组列表比较

Question

所以我正试图让我的列表字典与元组列表相匹配。(希望这是有道理的(。我有一本字典，里面有列表作为值，我的值是每本书的个人分数，例如：bob上的值5等于图书列表中的第一本书，：

d = {'bob':[5,0,0,1,3], 'toms':[3,0,5,3,0], 'sammy': [0,0,0,1,0], 'ted':[5,0,0,6,3]}

和元组列表：

books=[('Douglas Adams', "The Hitchhiker"), ('Richard Adams', 'Watership'), ('Mitch Albom', 'The Five People'), ('Laurie Anderson', 'Speak'), ('Maya Angelou', 'Caged Bird Sings')]

所以我希望能够说，当某人的评分为3或6时，我可以把他们拉出来，告诉他们哪些书有这些评分。谢谢

编辑：我希望它能输出一本字典，上面写着：

selectScores = {bob: ('Maya Angelou', 'Caged Bird Sings'), toms: (Maya Angelou', 'Caged Bird Sings', Laurie Anderson', 'Speak')} 

依此类推每个人

像这样的东西，我希望成为输出。

Answer 1

您可以尝试这样的方法。基本上枚举dictionary值并使用它的索引来访问books数组。

d = {'bob':[5,0,0,1,3], 'toms':[3,0,5,3,0], 'sammy': [0,0,0,1,0], 'ted':[5,0,0,6,3]}
books=[('Douglas Adams', "The Hitchhiker"), ('Richard Adams', 'Watership'), ('Mitch Albom', 'The Five People'), ('Laurie Anderson', 'Speak'), ('Maya Angelou', 'Caged Bird Sings')]
select_scores = {}
for key, books_scores in d.items():
for i, score in enumerate(books_scores):
if score == 3 or score == 6:
if key not in select_scores:
select_scores[key] = []
select_scores[key].append(books[i])

print(select_scores)

输出：

{'bob': [('Maya Angelou', 'Caged Bird Sings')], 'toms': [('Douglas Adams', 'The Hitchhiker'), ('Laurie Anderson', 'Speak')], 'ted': [('Laurie Anderson', 'Speak'), ('Maya Angelou', 'Caged Bird Sings')]}