当代码第二次循环时，bs4中出现错误

Question

from bs4 import BeautifulSoup
import requests

murl = ['https://www.amazon.in/dp/B07XY541GH/','https://www.amazon.in/dp/B085J17VVP/']
def track(url):
req = requests.get(url)
soup = BeautifulSoup(req.content, 'html5lib')
pr = soup.find('span', id='priceblock_ourprice').getText()
con_pr = pr[1:]
converted_price = con_pr.strip()
newprice = ''
for con in converted_price:
if con != ',':
newprice = newprice + con
newprice = float(newprice)
return newprice
def main():
for url in murl:
price = track(url)
print(price)
main()

当代码第二次循环时，我似乎总是明白这一点。即使我将url存储在两个不同的变量中，并逐个调用函数，我仍然会得到相同的错误。

2990.0
Traceback (most recent call last):
File "test.py", line 28, in <module>
main()
File "test.py", line 25, in main
price = track(url)
File "test.py", line 13, in track
pr = soup.find('span', id='priceblock_ourprice').getText()
AttributeError: 'NoneType' object has no attribute 'getText'

有什么解决办法吗？

Answer 1

以下是解决方案，请尝试：

import requests
from bs4 import BeautifulSoup
murl = ['https://www.amazon.in/dp/B07XY541GH/', 'https://www.amazon.in/dp/B085J17VVP/']

def track(url):
req = requests.get(url, headers={
"user-agent": "Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/88.0.4324.87 Safari/537.36"})
soup = BeautifulSoup(req.content, 'html5lib')
pr = soup.find('span', id=lambda x: x and x.startswith('priceblock_')).text
con_pr = pr[1:]
converted_price = con_pr.strip()
newprice = ''
for con in converted_price:
if con != ',':
newprice = newprice + con
newprice = float(newprice)
return newprice

def main():
for url in murl:
price = track(url)
print(price)

main()

1. 使用错过的用户年龄。大多数情况下，它应该用于解析
2. 元素标记对象没有getText((方法
3. 两个站点的Id不相同