使用字典动态序列化具有属性的Json对象

Question

我需要用字典动态序列化对象的响应。留下了json示例。

我试图在C#类中序列化这个响应对象(request_validator(，但这不起作用。有人能帮我吗，有什么想法吗？

{
"person": {
"testing": "CC",
"simple": "1234545",
"errorNames": {
"id": "655789",
"error": "simple"
},
"errorColor": {
"id": "2",
"error": "error color"
}
}
}
{
"request_validator": [
{
"person.errorNames": [
"error names"
],
"person.errorColor": [
"error color"
]
}
]
}

代码：

public class DeserializeResponse
{
public Dictionary<string, List<string>> request_validator { get; set; }
}
var error = JsonConvert.DeserializeObject<List<DeserializeResponse>>(content);

Answer 1

您可以使用Newtonsoft.Json库将字符串数组中的所有属性获取到字典中

在这种情况下，您只需要指向搜索级别的

using Newtonsoft.Json.Linq;
...
JObject validator = JObject.Parse(content);
IJEnumerable<JToken> validatorTokens = validator.SelectTokens("request_validator")?.Values();
Dictionary<string, List<string>> errors = new Dictionary<string, List<string>>();
if (validatorTokens != null)
{
foreach (JProperty prop in validatorTokens.Values())
{
if (!errors.ContainsKey(prop.Name))
{
errors.Add(prop.Name, new List<string>());
}
errors[prop.Name].Add(prop.Value?.ToString());
}
}

Answer 2

public class DeserializeResponse
{
[JsonPropertyName("request_validator")]
public RequestValidator[] RequestValidator { get; set; }
}
public class RequestValidator
{
[JsonPropertyName("person.errorNames")]
public string[] PersonErrorNames { get; set; }
[JsonPropertyName("person.errorColor")]
public string[] PersonErrorColor { get; set; }
}

var error = JsonSerializer.Deserialize<DeserializeResponse>(content);