我使用开关大小写和枚举来更改按钮的文本，但它无法正常工作

Question

所以我尝试使用开关大小写和枚举来更改按钮的文本，因为我不想使用太多的"如果"；声明。但是，按钮文本没有正确显示。例如，actionButton1.text不是"保存游戏"；但是"；SAVE_NAME"；。

ActionType.cs

using System.Collections;
using System.Collections.Generic;
using UnityEngine;
public enum ActionType {
    SAVE_GAME,
    LOAD_GAME,
    PAUSE_GAME
};
[CreateAssetMenu(fileName = "New Action", menuName = "Project/New Action")]
public class Action : ScriptableObject
{
    public ActionType actionType;
    public string actionName;
    public void Awake() {
        switch (actionType) {
            case ActionType.SAVE_GAME:
                actionName = "Save Game";
            break;
            case ActionType.LOAD_GAME:
                actionName = "Load Game";
            break;
            case ActionType.PAUSE_GAME:
                actionName = "Pause Game";
            break;
        }
    }
}

System.cs

using System.Collections;
using System.Collections.Generic;
using UnityEngine;
using UnityEngine.UI;
public class System : MonoBehaviour {
    public Text actionButton1;
    public Text actionButton2;
    public Text actionButton3;
    public Action action1;
    public Action action2;
    public Action action3;
    private void Start() {
        refreshAction();
    }
    private void refreshAction() {
        actionButton1.text = action1.actionName;
        actionButton2.text = action2.actionName;
        actionButton3.text = action3.actionName;
    }
}

Answer 1

在您的情况下，我会使用延迟评估

public class Action : ScriptableObject
{
    public ActionType actionType;
    public string actionName
    {
        get
        {
            switch(actionType)
            {
                switch (actionType) {
                    case ActionType.SAVE_GAME:
                        return "Save Game";
                    case ActionType.LOAD_GAME:
                        return "Load Game";
                    case ActionType.PAUSE_GAME:
                        return "Pause Game";
                }
                return "invalid action type";
            }
        }
    }
    ...
}

以便在更改代码时防止出现序列化问题。否则，您已经创建的可编写脚本的对象将保存旧数据(因为它们正在序列化(。

另一种方法是使用扩展方法使类似actionButton1.text = action1.actionType.ToReadableString();的调用成为可能。