希望接收来自用户的参数，并将它们放到函数中

Question

我想从用户那里获取参数并在函数中使用它们，但类型不同。

注意：正确工作的代码底部有一个注释但我想直接得到论点

感谢您的帮助

from string import ascii_letters
def encrypt(string , key):
    alpha = ascii_letters
    result = ''
    for ch in string : 
        if ch not in alpha :
            result += ch
        else :
            new_key = (alpha.index(ch) + key.str() ) % len(alpha)
            result += alpha[new_key]
    return result
def decrypt(string , key):
    key *= -1
    return encrypt(string , key)
state = ''
print("please enter 'e' to encrpyt & type 'd' to decrpyt :...")
state = input()
if state == 'e' : 
    print("please enter the str that you want to encrypt :... ")
    c_str1 = input()
    print("nplease enter the key that shifts strings(e.x. 1 to 52):... ")
    c_in1=input()
    encrypt(c_str1, c_in1)
elif state == 'd':
    print("please enter the str that you want to decrypt :... ")
    c_str= input('')
    print("nplease enter the key (e.x. 1 to 52):... ")
    c_in = input()
    decrypt(c_str, c_in )
   
# print(decrypt('amir',4))

Answer 1

不确定你的问题是什么，这里我尝试让你的代码运行，不确定是否按预期运行：

from string import ascii_letters
def encrypt(string , key):
    result = ''
    alpha = ascii_letters
    for ch in string : 
        if ch not in alpha :
            result += ch
        else :
            new_key = (alpha.index(ch) + int(key))  % len(alpha)
            
            result += alpha[new_key]
    return result
def decrypt(string , key):
    key *= -1
    return encrypt(string , key)

state = ''
print("please enter 'e' to encrpyt & type 'd' to decrpyt :...")
state = input()
if state == 'e' : 
    print("please enter the str that you want to encrypt :... ")
    c_str1 = input()
    print("nplease enter the key that shifts strings(e.x. 1 to 52):... ")
    c_in1 = input()
    print(encrypt(c_str1, c_in1))
elif state == 'd':
    print("please enter the str that you want to decrypt :... ")
    c_str = input()
    print("nplease enter the key (e.x. 1 to 52):... ")
    c_in = int(input())
    print(decrypt(c_str, c_in ))