week_milli_seconds = []
week_time = []
startDate = new Date(2020, 7, 17, 0, 0, 0)
startTime = startDate.getTime()
endTime = startTime + (week_milli_seconds - 1)
for( let i = 0; i < 10; i++) {
week_time.push({Start : startTime, End: endTime})
startTime += week_milli_seconds
endTime += week_milli_seconds
}
// console.log(startTime)
// console.log(endTime)
totalStartTime = new Date(2020, 7, 17, 0, 0, 0)
totalEndtime = Date.now()
console.log(week_time)
{ Start: 1597636800000, End: 1597636799999 },
{ Start: '1597636800000', End: '1597636799999' },
{ Start: '1597636800000', End: '1597636799999' },
{ Start: '1597636800000', End: '1597636799999' },
{ Start: '1597636800000', End: '1597636799999' },
{ Start: '1597636800000', End: '1597636799999' },
{ Start: '1597636800000', End: '1597636799999' },
{ Start: '1597636800000', End: '1597636799999' },
{ Start: '1597636800000', End: '1597636799999' },
{ Start: '1597636800000', End: '1597636799999' }
]
这是我得到的结果,但我试图在不同的几周内获得不同的值。我尝试了+=运算符,但它不起作用。提前感谢
一个空数组被分配给week_milli_seconds
。当给定一个数字和一个数组时,+
运算符将数组的每个成员和数字连接到一个字符串:
12 + [1,2,3] // "121,2,3"
由于您的数组是空的,这相当于将一个数字连接到""
。
您应该将week_milli_seconds
初始化为604 800 000 (1000 * 3600 * 24 * 7)
week_milli_seconds
是一个空数组。因此,+=
运算符试图向时间添加一个空数组,该数组只是再次返回原始时间,但作为字符串。将其更改为week_milli_seconds = 604800000
。
首先,week_milli_seconds = []
是一个数组,但您将其添加到不同的数字中,我猜您希望将其设置为一周内的总毫秒数,以实现
week_milli_seconds = 1000 * 60 * 60 * 24 * 7
我不太熟悉日期库,但假设startDate.getTime()
返回一个类似于Date.now的long
类型的日期字符串,但相对于那个时间,那么它现在应该可以工作了
您从未设置过变量week_milli_seconds
,那么它该如何工作呢?你必须给它一个值,这样你就可以用这个值增加或减少另一个变量。
问题是week_milli_conds是一个数组。请考虑为它指定一些值,而不是一个空数组。
以下代码应该可以工作。
let week_milli_seconds = 604800000
let week_time = []
let startDate = new Date(2020, 7, 17, 0, 0, 0)
let startTime = startDate.getTime()
let endTime = startTime + (week_milli_seconds - 1)
for( let i = 0; i < 10; i++) {
week_time.push({Start : startTime, End: endTime})
startTime += week_milli_seconds
endTime += week_milli_seconds
}
console.log(week_time)